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1 year ago

If a reaction occurs, what will be the products of the unbalanced reaction below?Zn(s) + HCl(aq) -->

Chemistry

1 answer:

irakobra [83]1 year ago

3 0

The products will be $ZnCl_2(s) + H_2(g)$

<h3>Chemical reactions</h3>

Zn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.

The equation of the reaction becomes: $Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)$

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

More on chemical reactivity can be found here: brainly.com/question/9621716

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How do the bonds within AND between a water molecule affect the properties of water?

Anuta_ua [19.1K]

Water is a polar molecule, meaning the covalent bonds in it share electrons unequally. They spend more time around the oxygen, making it positive and the hydrogens negative. This helps water stick to surfaces, a property called adhesion. The hydrogens of one molecule are also attracted to the oxygens of another. This is called cohesion, and it helps water form droplets

8 0

2 years ago

an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m

bogdanovich [222]

Answer:

$P_2=1.1x10^6Pa$

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

$P_1V_1=P_2V_2$

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

$P_2=\frac{P_1V_1}{V_2}$

Consider that the given initial pressure is also equal to Pa:

$P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa$

Which stands for a pressure increase when volume decreases.

Regards.

4 0

2 years ago

How many liters of carbon dioxide will be produced when 89.5 L of ethane are burned? (One mole of any gas occupies 22.4 L under

yan [13]

Answer:

179 L of CO2

Explanation:

Given the equation of the reaction;

C2H6(g) + 7/2 O2(g) -------> 2CO2(g) + 3H2O(g)

Now 1 mole of ethane yields 2 moles of CO2 from the balanced reaction equation

1 mole of a gas occupies 22.4 L volume so,

22.4 L of ethane yields 44.8 L of CO2

89.5 L of ethane yields 89.5 * 44.8/22.4 = 179 L of CO2

4 0

2 years ago

Can isotopes have different atomic numbers

Tpy6a [65]

Answer:

Explanation:

Atomic number represents the identity of atoms

using number of protons which is equal in isotopes.

6 0

2 years ago

Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of

Kaylis [27]

Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

a) moles of $H_2$

$\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles$

b) moles of $I_2$

$\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles$

$H_2(g)+I_2(g)\rightarrow 2HI(g)$

According to stoichiometry :

1 mole of $I_2$ require 1 mole of $H_2$

Thus 0.0787 moles of $l_2$ require= $\frac{1}{1}\times 0.0787=0.0787moles$ of $H_2$

Thus $l_2$ is the limiting reagent as it limits the formation of product and $H_2$ acts as the excess reagent. (10.0-0.0787)= 9.92 moles of $H_2$ are left unreacted.

Mass of $H_2=moles\times {\text {Molar mass}}=9.92moles\times 2.01g/mol=19.9g$

Thus 19.9 g of $H_2$ remains unreacted.

5 0

2 years ago