Need help with balance equation in chemistry

When 2 grams of powdered lead (IV) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Lead (IV) ox

kirza4 [7]

Answer:

The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

Explanation:

Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen using Lead (IV) oxide as a catalyst.

The catalyst surface area is directly proportional to the reaction rate

So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.

2. Also, Removing lead (IV) oxide from the reaction mixture the reaction rate decreased because as the catalyst is removed.

3. Using 50 cm³ of hydrogen peroxide doesn't affect the rate because the concentration of the reactant doesn't change.

4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased

So, The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

7 0

4 years ago

Given that the approximate bond length of o–h in water is roughly 1 å, what is the approximate distance each proton "hops" betwe

Ksenya-84 [330]

The hydrogen bond is a comparatively weak interaction between a proton hop and an electronegative atom present in a molecule. The hydrogen bond plays a very important role for the determination of state of a compound like gaseous, liquid or solid. The strength of the hydrogen bond depends on the close distance between the participants i.e. the electronegative atom and proton hop. There remains strong hydrogen bond between the two water molecules which is expressed as O....H. The distance of the hydrogen bond is 1.8A° formed between each proton hops of two neighboring water molecules. The hydrogen bond interaction is shown in the figure.

6 0

3 years ago

How many formula units of iron(III) oxide can be produced from the reaction of 108 g of iron with 72.1 L of oxygen gas at STP?

Irina-Kira [14]

Answer:

5.81 x 10^23 formula units Fe2O3

Explanation:

5 0

3 years ago

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0

3 years ago

The valence electrons largely determine the

ss7ja [257]

Valence electrons largely determine the chemical properties of an element.

8 0

3 years ago