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sertanlavr [38]
2 years ago
5

Need help with balance equation in chemistry

Chemistry
1 answer:
emmasim [6.3K]2 years ago
6 0
The balance is A Go check other answer I posted
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A mixture contains only NaCl and Al2(SO4)3. A 1.45-g sample of the mixture is dissolved in water, and an ex- cess of NaOH is add
chubhunter [2.5K]

Answer:

The mass percent of aluminum sulfate in the sample is 16.18%.

Explanation:

Mass of the sample = 1.45 g

Al_2SO_3+6NaOH\rightarrow 2Al(OH)_3+3Na_2SO_4

Mass of the precipitate = 0.107 g

Moles of aluminum hydroxide = \frac{0.107 g}{78 g/mol}=0.001372 mol

According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .

Then 0.001372 moles of aluminum hydroxide will be obtained from:

\frac{1}{2}\times 0.001372 mol=0.000686 mol

Mass of 0.000686 moles of aluminum sulfate :

= 0.000686 mol × 342 g/mol = 0.2346 g

The mass percent of aluminum sulfate in the sample:

=\frac{ 0.2346 g}{1.45g}\times 100=16.18\%

5 0
3 years ago
In process in which An animal's cells use oxygen and digested food molecules to release the energy in food is called
mamaluj [8]
In process in which An animal's cells use oxygen and digested food molecules to release the energy in food is called

cellular respiration
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3 years ago
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How many orbitals are in the f sublevel?
lord [1]

Answer:

7 orbitals

Explanation:

An f sublevel has 7 orbitals

7 0
3 years ago
Calculate the number of grams of Hydrogen required to produce 5.73 grams of water. 2H2+O2--->2H2O 2 grams 0.636 grams 1.2 gra
rusak2 [61]

Explanation:

32

2H

2

+O

2

→2H

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O

Molecular mass of H

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=2 g/mol

Molecular mass of O

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=32 g/mol

From the balanced chemical equation,

2×2=4 g of hydrogen requires 32 g of Oxygen to react completely

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The equal areas law is Keplers 2nd law of motion of planetary motion. It states that _____
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An imaginary line joining a planet and the sun sweeps out an equal area of space in equal amounts of time. Thus, the speed of the planet increases as it nears the sun and decreases as it recedes from the sun.

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