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Naya [18.7K]
3 years ago
14

What is the chemical symbol for element 2

Chemistry
1 answer:
Margarita [4]3 years ago
5 0
Looking at the elements from period three, you can identify element 2 based on element 3. It shows that element 3 is Magnesium. The ionization energy increases as it goes from left to right.

Since Element 2 has a lower ionization, just think of an atom that is to the left of Magnesium because it has a lower ionization energy. The only atom to the left of Magnesium is Sodium. So element 2 is Na, or Sodium. 
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ArbitrLikvidat [17]

Answer:

Explanation:

B I got it right

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In bullet points: explain the difference between thermal energy, heat and temperature.
sergeinik [125]
  • Thermal Energy- is the energy that comes from heat. This heat is generated by the movement of tiny particles within an object. The faster these particles move, the more heat is generated.

  • Heat-energy is the result of the movement of tiny particles called atoms, molecules or ions in solids, liquids and gases. Heat energy can be transferred from one object to another. The transfer or flow due to the difference in temperature between the two objects.

  • Temperature- is a measure of how hot or cold something is; specifically, a measure of the average kinetic energy of the particles in an object, which is a type of energy associated with motion.
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3 years ago
Lab: Calorimetry and Specific Heat
gayaneshka [121]

Answer:

Title for the lab--->Calorimetry and Specific Heat

Name:

Teacher:

Date:

Purpose: Explore how the specific heat of a substance can be determined using a “coffee cup” calorimeter.

Question: How can you determine the specific heat of a metal using a calorimeter?

Hypothesis: If a metal has a low specific heat, then the metal could make an excellent material for cookware because it takes less heat to raise the temperature of the metal to cook food.

MATERIALS:

- Two polystyrene coffee cups

- Lid for polystyrene cup

- Thermometer      

- 250 mL beaker        

- 400 mL beaker    

- Ring stand    

- Two buret clamps    

- Hot plate  

- Test-tube holder    

- 50 mL graduated cylinder  

- Water    

- aluminum, copper, iron, and lead powder    

- Analytical balance

PROCEDURE:

1) Set up a 600 mL beaker and add 400 mL of dis"lled water inside and place it on a hot plate un"l it boils. Also set up 2 dry Styrofoam cups with a lid aside and add 100.0 mL tap water (calorimeter water) inside.

2) In the boiling water, place the unknown metal sample inside for about 30 min. Before though, weigh it accurately and record the mass on your data sheet.

3) After 30 min, take the temperature of boiling water to the nearest 0.1 °C (Ini"al temp of metal), then take the metal out of the boiling water and replace it into Styrofoam cups filled with room temperature tap water. Ini"al temperature of water is the room temperature of the tap water.

4) Take every 15 seconds for about 2 minutes the temperature of water inside the calorimeter with a thermometer inserted through the hole in the lid. Gently swirl the cup to mix the contents and record the temperature. Use the highest temperature.

5) Calculate the specific heat of the metal sample.

then the table will be in the picture i posted on here  

next is your ---> Analysis /Conclusion

Analysis:

Analyzed from the data above, we know the temperature that is measured depends on the amount of mole in the solution. If the amount of mole in the solution is large, the temperature will be as well. After a few moments, the temperature rises and falls, and in some instances, it remains steady.

Conclusion:

In conclusion, I do believe my hypothesis was supported through my experiments. Through said experiments, I identified the unknown metal as we calculated the changes in the heat, and found that the metals that should be put to use are copper and iron metals. Copper and iron have a low specific heat, which makes these ideal metals when creating cookware. When a metal has low specific heat, it needs less energy to produce heat and it cools down with less energy as well. For these reasons, my hypothesis is supported.

Explanation:

hope this helps :)

5 0
2 years ago
If an acid has a Ka of 4.3 × 10-7 and a base has a Kb of 5.6 × 10-4, then what will be true about the salt produced? A. The salt
blsea [12.9K]

If an acid has a Ka of 4.3 × 10-⁷ and a base has a Kb of 5.6 × 10-⁴, then the true statement about the salt produced is that the salt would decrease the pH of the solution.

<h3>What is acid and base constant?</h3>

An acid dissociation constant, Kₐ, is a quantitative measure of the strength of an acid in solution while Kb indicates the high level of dissociation of a strong base.

According to this question, an acid has a Ka of 4.3 × 10-⁷ and a base has a Kb of 5.6 × 10-⁴. This shows that the strength of the base is higher than that of the acid.

Therefore, if an acid has a Ka of 4.3 × 10-⁷ and a base has a Kb of 5.6 × 10-⁴, then the true statement about the salt produced is that the salt would decrease the pH of the solution.

Learn more about Ka at: brainly.com/question/16035742

#SPJ1

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Part D<br> Explain how your model is different from the model in the picture.
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Answer:

I am explain you in image

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