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kirza4 [7]
2 years ago
15

The voltage between two parallel plates separated by a distance of 3.0 cm is 120 v. the electric field between the plates is:___

______
Physics
1 answer:
soldier1979 [14.2K]2 years ago
4 0

The electric field between two plates is 40 V/m.

To find the electric field between two plates, the values are given are,

distance =  3 cm

Voltage v = 120 v

<h3>What is electric field between two plates?</h3>

           The electric field between plates is the area where the charges between two plates, influences can be seen. For example, if a charged particle is placed near any charged plate, the plate exerts an electric force to attract or repel the charged particle.

Formula is given as,

                        E = V / d (v/m)

Substituting the given values,

                           = 120 /3

                           =40 v/m

Hence, the answer is 40 v/m.

Learn more about electric field,

brainly.com/question/8971780

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A small, 300 g cart is moving at 1.20 m/s on an air track when it collides with a larger, 2.00 kg cart at rest?
stiv31 [10]

Answer:

The speed of the large cart after collision is 0.301 m/s.

Explanation:

Given that,

Mass of the cart, m_1 = 300\ g = 0.3\ kg

Initial speed of the cart, u_1=1.2\ m/s

Mass of the larger cart, m_2 = 2\ kg

Initial speed of the larger cart, u_2=0

After the collision,

Final speed of the smaller cart, v_1=-0.81\ m/s (as its recolis)

To find,

The speed of the large cart after collision.

Solution,

Let v_2 is the speed of the large cart after collision. It can be calculated using conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

m_1u_1+m_2u_2-m_1v_1=m_2v_2

v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\dfrac{0.3\times 1.2+0-0.3\times (-0.81)}{2}

v_2=0.301\ m/s

So, the speed of the large cart after collision is 0.301 m/s.

4 0
3 years ago
What the exercise or play in the p.e in the philippines?<br> please!!!!, please!!!!
Debora [2.8K]

Answer:

They could be jumping off structures, running or climbing on rocks. They also could be participating in sports like soccer.

Explanation:

sources:

https://www.philippinesbasiceducation.us/2013/06/physical-activity-and-physical.html - about there play schedule

http://sportphil.com/category/articles/  - concil of philippines

Sorry that's all I could find.

5 0
3 years ago
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By moving a 20 nC charge from point A to point B, you determine that the electric potential at B is 100 V . Part A What would be
ivolga24 [154]

Answer:

Potential at B would be 100V

Explanation:

The electric potential is defined as the work done to bring a unit positive charge from infinity to some point in the field.

We always determine the potential with respect to some reference point. Let the potential at A be zero. If the potential at B is V, then work done to bring charge q from A to B = qV

which is the electric potential energy.

If instead we use some charge Q, the electric potential <em>energy</em> will be QV, but the electric potential will always be V.

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3 years ago
The electrons between atoms in metallic bonds
Scilla [17]

Answer:

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize.

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The weight of an astronaut plus his space suit on the Moon is only 319 N. How much (in N) do they weigh on Earth?
zheka24 [161]

Answer:

The weight of an astronaut plus his space suit on the Earth is 1,931.69 N.

Explanation:

Newton's second law, called the fundamental law or fundamental principle of dynamics, states that a body accelerates if a force is applied to it. This law indicates that the net force applied on a body is proportional to the acceleration that the body acquires. The constant of proportionality is the mass of the body, so Newton's second law is expressed in the following formula:

F = m*a

Where:

  • F is the net force. It is expressed in Newton (N)
  • m is the mass of the body. It is expressed in kilograms (Kg).
  • a is the acceleration that the body acquires. It is expressed in meters over second squared (m/s²).

The weight of an astronaut plus his space suit on the Moon is only 319 N. Then, being:

  • F= weight= 319 N
  • m= ?
  • a = acceleration of the Moon's gravity, whose value is 1.62 m/s²

you get:

319 N= m* 1.62 m/s²

Solving:

m=\frac{319 N}{1.62 \frac{m}{s^{2} } }

m=196.91 kg

The mass is an invariable quantity, regardless of the planet in which the astronaut plus his space suit on the Moon is, then you have:

  • F= weight= ?
  • m= 196.91 kg
  • a = acceleration of the Earth's gravity, whose value is 9.81 m/s²

replacing in the definition of force:

Weight= 196.91 kg* 9.81 m/s²

Weight= 1,931.69 N

<u><em>The weight of an astronaut plus his space suit on the Earth is 1,931.69 N.</em></u>

6 0
3 years ago
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