The weight of the meterstick is:

and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance

from the pivot.
The torque generated by the weight of the meterstick around the pivot is:

To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:

from which we find the value of d2:

So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.
Answer:OD. a hummingbird moving at 25 mph
Explanation:
Answer: a) The rate constant, k, for this reaction is
b) No
does not depend on concentration.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Given: Order with respect to
= 1
Thus rate law is:
a) ![Rate=k[A]^1](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5E1)
k= rate constant
![0.00250=k[0.484]^1](https://tex.z-dn.net/?f=0.00250%3Dk%5B0.484%5D%5E1)

The rate constant, k, for this reaction is
b) Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
Half life is the amount of time taken by a radioactive material to decay to half of its original value.


Thus
does not depend on concentration.
Answer:
Q = 4.52 10¹⁷ J
Explanation:
Thermal energy can be calculated with
Q = m c_{e} ΔT
in this case it indicates that we approximate seawater to pure water with
c_{e} = 4186 J/ kg K
with the density
ρ = m / V
m = ρ V
V = L³
we substitute
m = ρ L³
Q = ρ L3 c_{e} ΔT
calculate
Q = 1000 (3 103) 3 4186 4
Q = 4.52 10¹⁷ J