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Pani-rosa [81]
4 years ago
9

А

Physics
1 answer:
timurjin [86]4 years ago
8 0

Answer:

i hope it will be useful for you

Explanation:

F=5.6×10^-10N

R=93cm=0.93m

let take m1 and m2 =m²

according to newton's law of universal gravitation

F=m1m2/r²

F=m²/r²

now we have to find masses

F×r²=m²

5.6×10^10N×0.93m=m²

5.208×10^-9=m²

taking square root on b.s

√5.208×10^-9=√m²

so the two masses are m1=7.2×10^-5

and m2=7.2×10^-5

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A car traveling in a straight line has a velocity of 3.29 m/s at some instant. After 4.99 s, its velocity is 8.29 m/s.
seraphim [82]

Use the definition of average acceleration:

<em>a</em> = ∆<em>v</em> / ∆<em>t</em>

We have

<em>a</em> = (8.29 m/s - 3.29 m/s) / (4.99 s)

<em>a</em> = 1.002 m/s²

4 0
3 years ago
Determine the amount of time for polonium-210 to decay to one fourth its original quantity. The half-life of polonium-210 is 138
ira [324]

Answer: 276 days

Explanation:

This problem can be solved using the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)  

Where:  

A=\frac{1}{4}A_{o} is the final amount of the material

A_{o} is the initial amount of the material  

t is the time elapsed  

h=138 days is the half life of polonium-210

Knowing this, let's substitute the values and find t from (1):

\frac{1}{4}A_{o}=A_{o}2^{\frac{-t}{138 days}} (2)  

\frac{A_{o}}{4A_{o}}=2^{\frac{-t}{138 days}} (3)  

\frac{1}{4}=2^{\frac{-t}{138 days}} (4)  

Applying natural logarithm in both sides:

ln(\frac{1}{4})=ln(2^{\frac{-t}{138 days}}) (5)  

-1.386=-\frac{t}{138days}ln(2) (6)  

Clearing t:

t=276days (7)  

7 0
3 years ago
every morning Tom walks along a straight road from his home to a bus stop,a distance of 160 meters.The graph shows his journey o
Assoli18 [71]

Answer:

Tom walked until he was 100 metres from his home. Then, he realised that he had dropped his homework, so he turned around and went 60 metres to pick it up again. He again turned back and started to walk faster to get to the bus stop on time. He got to the bus stop 100 seconds after leaving his home and waited for the bus.

Explanation:

4 0
3 years ago
If an automobile's velocity changes from 25 m/s to 15m/s in 2s, then what is its acceleration?
tekilochka [14]
Hey!

u=25m/s
v=15m/s
t=2s
a=?

v-u=at
15-25=a×2
-10=2a
-10/2=a
a=-5m/s^2

Hope it helps...!!!
8 0
3 years ago
A clock is designed that uses a mass on the end of a spring as a timing mechanism. If the oscillation time needed is exactly one
user100 [1]

Answer:

The value is  k  =  51.34 \  N/ m

Explanation:

From the question we are told that

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5 0
3 years ago
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