Answer:
speed of truck (v) = 22 m/s ,
angle of hill (Θ) =15°
Find
Vertical component (Fv) = ?
Harizontal component (Fh) =?
Vertical component (Fh) = V cosΘ
= 22. cos 15
= 21.25 m/s.
Harizontal component (Fv) = V sinΘ
= 22. sin 15
= 5.69 m/s.
Answer:
Gravity, Friction, Air resistance, magnetism, static electricity
Explanation:
Answer:
Explanation:
Q₁ = 20 X 10⁻⁶ C
Q₂ = -45 X 10⁻⁶ C
d is required distance.
F = Force between the = 7 N
F = k x Q₁ X Q₂ / d²
d² = k x Q₁ X Q₂ / F = 20 X 45 X 10⁻¹² X 9 X 10⁹ /7
=1.157
d = 1.075 m
To solve this problem we will use the concepts related to the resulting Vector Force product of two components, that is,
If we take the Force of 50 N as the force in the X direction and the Force of 40 N in the Y direction we will have to:
Finally, since Newton's second law, acceleration can be determined as
Therefore the resultant magnitude of the acceleration of the object is 
Answer:
Here we do not have the vector, but I will try to give a kinda general solution to this type of problem.
If the vector is written as (a, b, c) we have that the force in the x-axis is of a Newtons, in the y-axis is of b Newtons, and in the z-axis is of c Newtons.
Then, we can calculate the total magnitude of this force as:
F = √( a^2 + b^2 + c^2)
wich gives us the total magnitude of the force, but not a direction or anything like that, this is just a scalar.
