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alekssr [168]
2 years ago
5

The distance between a carbon atom and an oxygen atom in the co molecule is how far from the carbon atom is the center of mass o

f the molecule?
Chemistry
2 answers:
DENIUS [597]2 years ago
5 0

The distance between a carbon atom and an oxygen atom in the co molecule is 0.63

<h3>What is the distance?</h3>

Distance is the measurement of the farness of two objects from each other.

The distance between the molecules can be calculated by the given formula

xcm = m_1+m_2m_1\times 1+m_2 \times 2

Putting the values in the equation

xcm = 12+1612 \times 0+16 \times 1.1 = 0.63 A^\circ

Thus, the distance between a carbon atom and an oxygen atom in the co molecule is 0.63

Learn more about distance

brainly.com/question/15172156

#SPJ4

Gwar [14]2 years ago
4 0

Answer:

1.12x10-10 or 0.63 ewan

Explanation:

Correct option is C)

The distance of centre of mass from carbon atom is,

xcm=m1+m2m1x1+m2x2

=12+1612×0+16×1.1

=0.63A˚

Thus, the centre of mass is 0.63A˚ from carbon atom.

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2 years ago
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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a
Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Average atomic mass = 48.68 amu

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Fractional abundance of heaviest-weight isotope = \frac{x}{100}

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

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Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] %  = (90 - x) %

Fractional abundance of middle-weight isotope = \frac{(90-x)}{100}

Now put all the given values in above formula, we get:

48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]

x=78\%

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3 years ago
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Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr
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What gas is used in respiration​
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Explanation:

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