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liubo4ka [24]
3 years ago
9

If the reactants contain one chlorine molecule, do you know how many chlorine atoms will be in the product? Include conversion o

f matter in your explanation.
Chemistry
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

The number of Chlorine atoms in the product is 2.

Explanation:

The law of conservation of mass states that matter can neither be created nor destroyed in a chemical reaction.

The reactants contain one chlorine molecule(Cl_{2}) which has two chlorine atoms.

Then, according to law of conservation of matter, the product must contain two chlorine atoms.

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Which of the following best describes the difference between a scientific theory and a scientific law?
Kryger [21]

Answer:

D im pretty sure cuz i prob had this test already

Explanation:

5 0
3 years ago
PLEASE ANSWER
Aleks [24]

Answer:

The answer is B. Jeff pushes on his box with twice the amount of force since his box has 1/2 the mass of Jim's box.

hope it helps!

6 0
3 years ago
Draw all of the Lewis structures of O2 which obey the octet rule and use this Lewis structure or these resonance structures to p
ryzh [129]

Answer:

Each oxygen atom is connected to the central O atom with 2 covalent bonds.

Explanation:

Oxygen atoms are connected by two covalent bonds in the oxygen molecule from the Lewis structure, we see that the bond order for O2 is 2 (a double bond) this is clearly seen in the image attached. There are no resonance structures for the oxygen molecule since there are no partial bonds in the molecule, only the two covalent bonds present.

This structure of oxygen shown in the image is its only structure, showing the covalent bonds formed and other non bonding electrons present in the molecule. The octet rule is followed in drawing the structure. Each oxygen atom possesses an octet of electrons on its outermost shell.

7 0
3 years ago
How many grams are in 2.54 x 10^23 molecules of CO2
Ivan

Answer:

=<em><u> 0.42 moles of CO2 </u></em>

Explanation:

From Avogadro's constant

6.02×10^23 molecules are in 1 mole of CO2

2.54×10^23 molecules will be in

=[(2.54×10^23) ÷ (6.02×10^23)]

= 0.42 moles of CO2

8 0
3 years ago
Calculate the freezing point of a solution made from 220g of octane (C Hua), molar mass = 114,0 gmol dissolved in 1480 g of benz
stiv31 [10]

Answer: Freezing point of a solution will be -1.16^0C

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(5.50-T_f)^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant = 5.12^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (benzene)= 1480 g =1.48 kg

Molar mass of solute (octane) = 114.0 g/mol

Mass of solute (octane) = 220 g

(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}

(5.50-T_f)^0C=6.68

T_f=-1.16^0C

Thus the freezing point of a solution will be -1.16^0C

3 0
3 years ago
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