Answer:
I'm not sure but I think it's 4.5 v
Answer:
The induced voltage in the coil is 0.25 V.
Explanation:
It is given that,
Area of a square coil is 2 cm or 0.02 m
Number of turns in the wire is 2500
A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.
We need to find the induced voltage in the coil. According to Faraday's law, the induced emf in the coil is given by the rate of change on magnetic flux. So,

So, the induced voltage in the coil is 0.25 V.
I believe it is positive.
Answer:
f = 409 Hz
Explanation:
We have,
Length of the open organ pipe, l = 0.29 m
Frequency of vibration of second overtone, 
It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

v is speed of sound
Let f is the fundamental frequency. It is given by :

The relation between f and f₂ can be written as :

So, the fundamental frequency of the pipe is 409 Hz.