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dexar [7]
1 year ago
10

Jonah is applying to be the editor of the school newspaper. In his interview he's asked why he believes he's the best person for

the job. He says that the other student who wants the position is a horrible writer. Which logical fallacy has Jonah used?
Ad hominem
Bandwagon
False analogy
Hasty generalization
please help and fast!!
Physics
1 answer:
Vikentia [17]1 year ago
4 0

The type of logical fallacy that Jonah has used is Hasty generalization. That is option D.

<h3>What is logical fallacy?</h3>

Logical fallacy is defined as those arguments that are based on false logics which may sound convincing but they are false.

Hasty generalisation is defined as the type of fallacy that is being made based on an insufficient evidence about another individual.

From the excerpt given, Jonah is a job seeker for the position of an editor of a school together with other applicants. He said that the other student who wants the position is a horrible writer.

There is no evidence to prove that the student is a bad writer therefore it's a Hasty generalization fallacy.

Learn more about fallacy here:

brainly.com/question/20939336

#SPJ1

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Answer:

3a, 2b,4c,1d

Explanation:

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3 years ago
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A uranium and iron atom reside a distance R = 44.10 nm apart. The uranium atom is singly ionized; the iron atom is doubly ionize
Ad libitum [116K]

Answer:

distance r from the uranium atom is 18.27 nm

Explanation:

given data

uranium and iron atom distance R = 44.10 nm

uranium atom = singly ionized

iron atom = doubly ionized

to find out

distance r from the uranium atom

solution

we consider here that uranium electron at distance = r

and electron between uranium and iron so here

so we can say electron and iron  distance = ( 44.10 - r ) nm

and we know single ionized uranium charge q2= 1.602 × 10^{-19} C

and charge on iron will be q3 = 2 × 1.602 × 10^{-19} C

so charge on electron is q1 =  - 1.602 × 10^{-19} C

and we know F = k\frac{q*q}{r^{2} }  

so now by equilibrium

Fu = Fi

k\frac{q*q}{r^{2} }  =  k\frac{q*q}{r^{2} }

put here k = 9*10^{9} and find r

9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{r^{2} }  =  9*10^{9}\frac{1.602 *10^{-19}*1.602 *10^{-19}}{(44.10-r)^{2} }

\frac{1}{r^{2} } = \frac{2}{(44.10 -r)^2}

r = 18.27 nm

distance r from the uranium atom is 18.27 nm

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A bicycle takes 8.0 seconds to accelerate at a constant rate from rest to a speed of 4.0 m/s. If the mass of the bicycle and rid
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Answer:

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In the scenario given, the experiment is to see the relationship between the <u>initial height of a basketball</u> and the <u>height of its rebound bounce. </u>

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