As close as I can read it, it appears to be
1/12 gram/second
(0.08333... gm/sec)
Oil is less dense than water so it tends to float on the top of the water. Hope this Helps!
Answer : The final pressure in the two containers is, 2.62 atm
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

Thus, the expression for final pressure in the two containers will be:


where,
= pressure of N₂ gas = 4.45 atm
= pressure of Ar gas = 2.75 atm
= volume of N₂ gas = 3.00 L
= volume of Ar gas = 2.00 L
P = final pressure of gas = ?
V = final volume of gas = (4.45 + 2.75) L = 7.2 L
Now put all the given values in the above equation, we get:


Thus, the final pressure in the two containers is, 2.62 atm
Answer:
c) Both the parts will weigh the same
Explanation:
center of gravity is based on weight so if you cut down the center of gravity you would have 2 equal parts
(might be D if it is cutting against the center of gravity)
As these are distances created by moving in a straight line, using a trigonometric analysis can solve the missing single straight-line displacement. Looking at the 48m and 12m movements as legs of a triangle, obtaining the hypotenuse using the pythagorean theorem will yield us the correct answer.
This is shown below:
c^2 = 48^2 + 12^2
c = sqrt(2304 + 144)
c = sqrt(2448)
c = 49.48 m
To obtain the angle at which Anthony walks 49.48, we obtain the arc tangent of (12/48). This is shown below:
arc tan (12/48) =14.04 degrees.
Therefore, Anthony could have walked 49.48 m towards the S 14.04 W direction.