Question

A piece of plastic has a net charge of +9.9 μC. How many more protons than electrons does this piece of plastic have? (e = 1.60 x 10^-19 C). (Divide your answer by 10^13, and give the result to the nearest 0.01

Answer 1

Answer:

The number of protons 6.19 more than electron.

Explanation:

Given that,

Charge $Q=+9.9\times10^{-6}\ C$

We know that,

formula of charge

$Q = nc$

Where,

Q = total charge

n = number of protons

e = charge of electron

Put the value into the formula

$n = \dfrac{Q}{e}$

$n=\dfrac{9.9\times10^{-6}}{1.6\times10^{-19}}$

$n=6.1875\times10^{13}\ C$

According to statement of question

Divide the answer by $10^{13}$

$n=\dfrac{6.1875\times10^{13}}{10^{13}}$

$n=6.19\ C$

Hence, The number of protons 6.19 more than electron.