S = u + at u = 0 278 = 3.7t t = 278/3.7 = 75.135.. v = ut + 0.5at^2 u = 0 v = 0.5 * 3.7 * 75.135^2 = 10,443 m/sec
If the current takes him downstream we must find the resultant vector of the velocities:

Then if the river is 3000 m-wide the swimmer will have to pass:
1.3520747 · 300 = 4056.14 m t = 4056.14 m : 1 m/s
a ) It takes
4056.15 seconds ( 1 hour 7 minutes and 36 seconds ) to cross the river.
b ) 0.91 · 3000 =
2730 mHe will be 2730 m downstream.
Answer:
here
Explanation:
There are two forces acting upon the skydiver - gravity (down) and air resistance (up). The force of gravity has a magnitude of m•g = (72 kg) •(9.8 m/s/s) = 706 N. ... a 3.25-kg object rightward with a constant acceleration of 1.20 m/s/s if the force of ... of 33.8 kg, how far (in meters) will it move in 1.31 seconds, starting from rest?
Answer:
a = change in v / change in time
= (5.2 - 11) / 3.1
= -1.87 m/s^2
Explanation:
Answer:

Explanation:
<h3><u>Given data:</u></h3>
Frequency = f = 200 Hz
Velocity = v = 400 m/s
<h3><u>Required:</u></h3>
Wavelength = λ = ?
<h3><u>Formula:</u></h3>
v = fλ
<h3><u>Solution:</u></h3>
Put the givens in the formula
400 = (200)λ
Divide 200 to both sides
400/200 = λ
2 m = λ
λ = 2 m
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)