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vlada-n [284]
1 year ago
5

I need help with my homework please?

Physics
2 answers:
Advocard [28]1 year ago
8 0

Answer:

it's easy bro once try yourself if you can't then l am here

netineya [11]1 year ago
7 0

Answer:

i need the describtion like what i need to do

Explanation:

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#2 Distance (d) = _______37.5cm____________
bixtya [17]

Answer:

Im not sure how to explain it but i need points im sorry

Explanation:

8 0
2 years ago
You find it takes 200 J of heat to take 4 kg of an unknown substance from 200 K to 240 K. It does not change phases during this
klasskru [66]

Answer:

300 K

Explanation:

First, we have find the specific heat capacity of the unknown substance.

The heat gained by the substance is given by the formula:

H = m*c*(T2 - T1)

Where m = mass of the substance

c = specific heat capacity

T2 = final temperature

T1 = initial temperature

From the question:

H = 200J

m = 4 kg

T1 = 200K

T2 = 240 K

Therefore:

200 = 4 * c * (240 - 200)

200 = 4 * c * 40

200 = 160 * c

c = 200/160

c = 1.25 J/kgK

The heat capacity of the substance is 1.25 J/kgK.

If 300 J of heat is added, the new heat becomes 500 J.

Hence, we need to find the final temperature, T2, when heat is 500 J.

Using the same formula:

500 = 4 * 1.25 * (T2 - 200)

500 = 5 * (T2 - 200)

100 = T2 - 200

=> T2 = 100 + 200 = 300 K

The new final temperature of the unknown substance is 300K.

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3 years ago
1150 g - 0.652 kg = ______________g?
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