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liberstina [14]
3 years ago
5

Two children who are bored while waiting for their flight at the airport decide to race from one end of the 20-m-long moving sid

ewalk to the other and back. Phillippe runs on the sidewalk at 2.0 m/s (relative to the sidewalk). Renee runs on the floor at 2.0 m/s. The sidewalk moves at 1.5 m/s relative to the floor. Both make the turn instantly with no loss of speed. a. Who wins the race
Physics
2 answers:
QveST [7]3 years ago
8 0

Answer: Phillipe wins the race

Explanation:

Given

Length of track=20 m

Velocity of Phillippe=2 m/s w.r.t sidewalk

Velocity of sidewalk=1.5 m/s

Rena velocity=2 m/s

Therefore absolute velocity of P is 2+1.5=3.5 m/s

Time taken by phillippe \frac{20}{3.5}+\frac{20}{3.5-1.5}

t_P=5.714+10=15.714 s

Time taken by rena

t_r=\frac{20}{2}+\frac{20}{2}=20 s

as the time taken  by phillippe is less than rena therefore Phillippe wins the race.

Usimov [2.4K]3 years ago
4 0

Answer:

Renee will win the race

Explanation:

Total time of motion for Phillippe is given as

t_1 = \frac{L}{v + v_1 } + \frac{L}{v - v_1}

now we have

t_1 = \frac{L}{2 + 1.5} + \frac{L}{2 - 1.5}

t_1 = \frac{L}{3.5} + \frac{L}{0.5}

t_1 = 2.28 L

now for Renee we have

t_2 = \frac{L}{2} + \frac{L}{2}

t_2 = L

so here we can see that

t_2 < t_1

so Renee will win the race

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67.8 turns needed by the secondary coil to run the bulb.

<u>Explanation</u>:

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\text { Electric power }(p)=\frac{V^{2}}{R}

\text { Hence, } \frac{P_{1}}{P_{2}}=\frac{V_{1}^{2} / R}{V_{2}^{2} / R}

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\frac{N_{P}}{N_{S}}=\frac{V_{P}}{V_{S}}

Given that,

80 \mathrm{W}\left(P_{1}\right) \text { bulb with voltage } 120 \mathrm{V}\left(V_{1}\right) \text { is connected to a transformer. }

\text { The source voltage of a transformer is }\left(V_{P}\right) \text { is } 65 \mathrm{V}

\text { The number of turns in primary winding of transformer is }\left(N_{P}\right) \text { is } 30 .

We need to find the number of turns in the secondary winding \left(N_{S}\right) to run the bulb at 120W \left(P_{2}\right)

Firstly find the secondary voltage in the transformer use, \frac{P_{1}}{P_{2}}=\frac{V_{1}^{2}}{V_{2}^{2}}

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V_{2}^{2}=\frac{1728000}{80}

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V_{2}=\sqrt{21600}

V_{2}=146.9 \mathrm{V}=V_{S}

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N_{S}=\frac{30 \times 146.9}{65}

N_{S}=\frac{4407}{65}N_{S}=67.8

The number of turns in the secondary winding are 67.8 turns.

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