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3 years ago

LAST ONE! ASAP PLEASE

Physics

2 answers:

Pie3 years ago

6 0

Answer:

Explanation:

Step 1: We make the assumption that 160 is 100% since it is our output value.

Step 2: We next represent the value we seek with x.

Step 3: From step 1, it follows that 100%=160

Step 4: In the same vein, = x%=140.

Step 5: This gives us a pair of simple equations:

100%=160(1).

x%=140(2).

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

100% / x% = 160 / 140

Step 7: Taking the inverse (or reciprocal) of both sides yields

x% / 100% = 140 / 160

x% = 87.5%

therefore, 140 is 87.5% of 160

Doss [256]3 years ago

4 0

Answer:

There are so many questions which one you don't know

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An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper

dimulka [17.4K]

Answer:

The power output of this engine is $P = 17.5 W$

The the maximum (Carnot) efficiency is $\eta_c = 0.7424$

The actual efficiency of this engine is $\eta _a = 0.46$

Explanation:

From the question we are told that

The temperature of the hot reservoir is $T_h = 1250 \ K$

The temperature of the cold reservoir is $T_c = 322 \ K$

The energy absorbed from the hot reservoir is $E_h = 1.37 *10^{5} \ J$

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substituting values

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$P = \frac{63000}{3600}$

$P = 17.5 W$

The Carnot efficiency is mathematically represented as

$\eta_c = 1 - \frac{T_c}{T_h}$

$\eta_c = 1 - \frac{322}{1250}$

$\eta_c = 0.7424$

The actual efficiency is mathematically represented as

$\eta _a = \frac{W}{E_h}$

substituting values

$\eta _a = \frac{63000}{1.37*10^{5}}$

$\eta _a = 0.46$

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Answer:

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Explanation:

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