Answer:
Explanation:
We know that the formula for acceleration is given by:
, where v = Final velocity
u= Initial velocity
Given : The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration.
i.e. u= 110 km/h
[∵ 1 km= 100 meters and 1 hour = 3600 seconds]
v= 0 m/s ( At brake , final velocity becomes 0)
t=4.5 seconds
Substitute all the values in the formula , we get

Hence, the average acceleration of the car during braking is
.
Answer:
The value is 
Explanation:
From the question we are told that
The mass of matter converted to energy on first test is 
The mass of matter converted to energy on second test 
Generally the amount of energy that was released by the explosion is mathematically represented as

=> ![E = 1.5 *10^{-3} * [ 3.0 *10^{8}]^2](https://tex.z-dn.net/?f=E%20%3D%20%201.5%20%2A10%5E%7B-3%7D%20%20%2A%20%5B%203.0%20%2A10%5E%7B8%7D%5D%5E2)
=> 
Answer:
Choice a. 1 kg, assuming that all other forces on the object (if any) are balanced.
Explanation:
By Newton's Second Law,
,
where
is the acceleration of the object in
,
is the net force on the object in Newtons, and
is the mass of the object in kilograms.
As a result,
.
Assume that all other forces on this object are balanced. The net force on the object will be
. The net force is constant. Acceleration should also be constant and the same as the average acceleration in the two seconds.
<h3>What is the
average acceleration of this object?</h3>
.
.
<h3>Apply Newton's Second Law to find the mass of the object.</h3>
.
The initial velocity of the stone is 0 ft/s. Given the initial velocity (Vi), final velocity (Vf), and acceleration due to gravity (g), the distance may be calculated through the equation,
d = ((Vf)² - (Vi)²) / 2g
Substituting the known values,
d = ((96 ft/s)² - 0))/ (2x32.2)
The value of d is 143.10 ft.