The concentration of A is initially 0.150 M before it proceeds to equilibrium. The system is at 298 K. What is the equilibrium c

Question

miskamm [114]

3 years ago

13

The concentration of A is initially 0.150 M before it proceeds to equilibrium. The system is at 298 K. What is the equilibrium c

oncentration of B

Chemistry

1 answer:

valina [46] · Answer 1 · 2023-01-03T02:19:50+03:00

For a concentration of is initially 0.150 M before it proceeds to equilibrium, the equilibrium concentration of B is mathematically given as

x=3.0*10^{-7}m

<h3>What is the equilibrium concentration of B?</h3>

Generally, the equation for the change in Gibbs free energy is mathematically given as

dG=-RTInK

Therefore

31.5*10*^{3}=-(8.314)(298)(ink)

K=3*10^(-6)

Eqution

A--->B

K=x/0.1-x

x=3.0*10^{-7}m

In conclusion, the equilibrium concentration

x=3.0*10^{-7}m