Since the molecular weight of water is about 18 g/mol, you have about 1 mol of water. So, now we know that it takes approximately 46.2 kJ of heat energy to warm 18.02g of water from 25C to 100C and then to vaporize it into steam. Hopefully this helped!
Explanation:
Answer:
This is a simple case of ratios. (1 mol)/(22.4 L)=(n mol)/(.025 L) Then we cross multiply and we get 22.4n=.025 We divide each side by 22.4 to find n=.001116 mol Then to convert the moles to atoms we multiply, and cross-cancel the units (.001116 mol)/1 xx (6.02 xx 10^23 atms)/(1 mol) and we have 6.72 xx 10^20 atoms. I've found the trick of cross-cancelling units to be a very effective mnemonic, it always makes sure you carry out the correct calculation to find the desired units.
Explanation:
I believe that the choices for this question are:
C2H4O2, C4H8O4 <span>
CH2O, C6H12O6
C3H6O3, C6H12O6
C2H4O2, C6H12O6 </span>
The answer to this based on the molar masses given is:
C2H4O2, C6H12O6
To prove calculate the molar mass:
C2H4O2 = 2*12 + 4*1 + 2*16 = 60
C6H12O6 = 6*12 + 12*1 + 6*16 = 180
Answer:
The density of beryllium is 1.85 g/cm³. Thus given metal is beryllium.
Explanation:
Given data:
Mass of metal = 37 g
Volume of metal = 20cm³
Which metal is this = ?
Solution:
We will solve this problem by using density formula. After finding density we will check from literature which metal has a density similar to our calculated density.
d = m/v
d = 37 g/ 20cm³
d = 1.85 g/cm³
The density of beryllium is 1.85 g/cm³. Thus given metal is beryllium.