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Naddik [55]
3 years ago
5

The specific heat of aluminum is 0.902 J/g C. If a one gram sample of aluminum absorbs 50 Joules of energy, how much with its te

mperature rise?
Chemistry
1 answer:
PtichkaEL [24]3 years ago
7 0
Answer:
55.4324℃
Explanation:
Q=cm△t
50J = 0.902J/(g·℃) x 1g x △t
△t =55.4324℃
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Assuming 100% dissociation, calculate the freezing point and boiling point of 1.22 m SnCl₄(aq). Constants may be found here.
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T° freezing solution → -11.3°C

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The formula for the colligative property of freezing point depression and boiling point elevation are:

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ΔT = Kb . m . i

where ΔT = T° boiling solution - T° boiling pure solvent

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0° - T° freezing solution = 1.86°C/m . 1.22 m . 5

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Boiling point elevation:

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8 0
3 years ago
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