Answer:


Explanation:
= Area of section 1 = 
= Velocity of water at section 1 = 100 ft/min
= Specific volume at section 1 = 
= Density of fluid = 
= Area of section 2 = 
Mass flow rate is given by

The mass flow rate through the pipe is 
As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

The speed at section 2 is
.
Answer:
Average heat transfer =42.448w/m^2k
Nud = 13.45978
Explanation:
See attachment for step by step guide
Answer:
Part A: (d/D=0.1)
DeltaV percent=42.6%
Part B:(d/D=0.01)
DeltaV percent=21.7%
Explanation:
We are going to use the following volume flow rate equation:

Above equation can be written as:


First Consider no wire i.e d/D=0
Above expression will become:


Part A: (d/D=0.1)




DeltaV percent=42.6%
Part B:(d/D=0.01)




DeltaV percent=21.7%
Explanation:
commands to be and function arguments