The answer is B hope this is right
Answer:
1. 35g NaCl.
2. 234g sugar.
3. 0.506L of concentrated nitric acid are needed.
4. 1.67L of 9.0M copper (II) sulfate are needed
Explanation:
Molarity is defined as the ratio between moles of solute and the volume of the solution.
1. 1.00L * (0.60mol / L) = 0.60 moles NaCl are dissolved
To convert moles to mass we must use its molar mass:
0.60mol NaCl * (58.44g/mol) =
35g NaCl
2. 2L * (0.342mol / L) = 0.684 moles Sugar = moles sucrose
0.684 mol * (342.30g / mol) = 234g sugar
3. 4L of a 2.0M are:
4L * (2.0mol/L) = 8moles
8mol * (1L / 15.8mol) = 0.506L of concentrated nitric acid are needed
4. 3.0L * (5.0 mol / L) = 15.0 moles copper (II) sulfate.
15.0mol * (1L / 9.0mol) = 1.67L of 9.0M copper (II) sulfate are needed
Answer:
evaperation
Explanation:
remaining energy is transferred from the earth surface by evaporation
<span>The balanced chemical equation for this reaction is:
2NaOH (aq)+H2SO4 (aq) → Na2SO4 (aq)+2H2O (l)
According to question, 60 ml of NaOH solution was used for neutralizing 40 ml of 0.50M H2SO4.
The no. of moles of H2SO4 is calculated using the equation:
mol solute = (molarity) (L soln)
mol H2SO4 = 0.50 M x 0.040 L = 0.02 moles of H2SO4
As per the equation, the number of moles of NaOH used is:
0.02 moles of H2SO4 (2 mol NaOH) (1 mol H2SO4) = 0.04 moles of NaOH
Therefore, using the given volume of NaOH, the concentration or molarity of NaOH can be calculated using the formula :
Molarity = mol solute/L soln = 0.04 mol NaOH/0.06 L = 0.67 M
Therefore, the concentration of NaOH is 0.67 M.</span>
