Solve for the linear/tangential speed:
<em>a</em> = <em>v</em>²/<em>r</em>
where <em>a</em> = centripetal acceleration, <em>v</em> = speed, and <em>r</em> = radius.
4.7 m/s² = <em>v</em>²/(0.3 m)
<em>v</em>² = (0.3 m) (4.7 m/s²)
<em>v</em> ≈ 3.96 m/s
For every time the record completes one revolution, a fixed point on the edge of the record travels a distance equal to its circumference, which is 2<em>π</em> (0.3 m) ≈ 1.88 m. So if 1 rev ≈ 1.88 m, then the angular speed of the record is
(3.96 m/s) (1/1.88 rev/m) ≈ 7.46 rev/s
Take the reciprocal of this to get the period:
1 / (7.46 rev/s) ≈ 0.134 s/rev
So it takes the record about 0.134 seconds to complete one revolution.
Answer:
The wave velocity is 1.3736
Explanation:
A plot of inverse of wavelength (λ) versus frequency (f), can be analyzed as follows;
The vertical axis will be 1/λ and the horizontal axis will be f
slope = (Δ1/λ)/(Δf)
= 1/(fλ)
∴ 1/(fλ) = 0.728
From wave equation, V = fλ
where;
V is the wave velocity
f is the frequency of the wave
λ is the wavelength
1/(fλ) = 0.728
1/(V) = 0.728
V = (0.728)⁻¹
V = 1.3736
Therefore, the wave velocity is 1.3736
Answer:
Explanation: O B. Diffraction
