I’m pretty sure it is A Electrode
Java is used to create independent applications maybe used on a single computer or maybe for a distributed computer network.
<u>Explanation:</u>
Java is a broadly useful programming language that is class-based, object-arranged, and intended to have as not many execution conditions as could be allowed.
Java is utilized to make independent applications which may run on a solitary PC or in circulated arrange. It is additionally be utilized to make a little application program dependent on applet, which is additionally utilized for Web page. Applets make simple and conceivable to collaborate with the Web page.
Answer:
Explanation:
The piston-cylinder system is modelled after the First Law of Thermodynamics:
The electrical energy supplied by the resistance heater is:
Let suppose that air behaves ideally, so that:
The initial specific volume is determined by the use of the equation of state for ideal gases:
The final specific volume can be derived from the following relationship:
The energy supply is:
Answer:
(a) Calculate the field, armature, and load currents versus load = 306A
(b) Determine the terminal voltage at no-load and at rated load conditions = 300V
(c) Calculate the voltage regulation of the generator. Use the no-load voltage as the base value = 6.67%
(d) Plot the terminal voltage as a function of the load. Determine the load that corresponds to a 5% voltage drop using the no-load voltage as the base = 294.74V
Explanation:
CHECK THE ATTACHED FILES FOR DETAILED EXPLANATION.
Answer:
R = 1 kΩ
i_L = 2.2 mA
Explanation:
The complete question is given in attachment:
Given:
- The gain i_L / i_i = 11
- Given circuit Attachment
Find:
- Find the required value of R
- If the amplifier is fed with a current source having a current of 0.2 mA and a source resistance of 10 kΩ, find iL
Solution:
- Use KVL on right most loop (load loop):
v_x = 0 - i_i*10 = -10i_i
- Using ohm's law:
i = (0 - v_x) / R
i = 10*i_i / R
- Use KCL at the node:
i_L = i + i_i
- Substitute the the two i:
i_L = 10*i_i / R + i_i
i_L / i_i = ( 10/ R + 1 )
11 = ( 10/ R + 1 )
10 / R = 10
R = 1 kΩ
- The input resistance = 0 because there is a virtual ground at input. Then the value of source resistance will have no effect on resulting i_l, hence:
i_L = i_L / i_i * i_i
i_L = 11*0.2
i_L = 2.2 mA