Answer:
a) 149 kJ/mol, b) 6.11*10^-11 m^2/s ,c) 2.76*10^-16 m^2/s
Explanation:
Diffusion is governed by Arrhenius equation

I will be using R in the equation instead of k_b as the problem asks for molar activation energy
I will be using

and
°C + 273 = K
here, adjust your precision as neccessary
Since we got 2 difusion coefficients at 2 temperatures alredy, we can simply turn these into 2 linear equations to solve for a) and b) simply by taking logarithm
So:

and

You might notice that these equations have the form of

You can solve this equation system easily using calculator, and you will eventually get

After you got those 2 parameters, the rest is easy, you can just plug them all including the given temperature of 1180°C into the Arrhenius equation

And you should get D = 2.76*10^-16 m^/s as an answer for c)
Answer:
6.5 × 10¹⁵/ cm³
Explanation:
Thinking process:
The relation 
With the expression Ef - Ei = 0.36 × 1.6 × 10⁻¹⁹
and ni = 1.5 × 10¹⁰
Temperature, T = 300 K
K = 1.38 × 10⁻²³
This generates N₀ = 1.654 × 10¹⁶ per cube
Now, there are 10¹⁶ per cubic centimeter
Hence, 
Answer:
Please see the attached file for the complete answer.
Explanation:
Answer:
water rise = 22 mm
Explanation:
weight of packet IN AIR = 40 *9.81 =392.4 N
weight of packet IN WATER= 18 *9.81 =176.58 N
by Archimedi's principle
difference in weight = weight of displaced water
w_a - w_w = \rho_w v_d g
392.4 - 176.58 = 1000* v_d* 9.81
v_d = 0.022 m^3
v_d = A*H_rise
0.022 =1*H_rise
H_rise = 0.022 m = 22 mm
water rise = 22 mm
Answer:
wool, rubber, and plastic
Explanation: