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Oksanka [162]
2 years ago
8

How does energy transition from one form to another as water moves from behind a dam to downstream of a dam?.

Engineering
1 answer:
Tresset [83]2 years ago
3 0

Answer:
potential energy changes to kinetic energy
Explanation:

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You doubled the voltage frequency in an RL series AC circuit, the inductive resistance would?
Ivenika [448]

Answer:

Remain the same.

Explanation:

If you doubled the voltage frequency in an RL series AC circuit, the inductive resistance would <u>remain the same</u>.

6 0
3 years ago
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Which of the following technologies will the design and development of a bicycle stand be categorized under?
Yuri [45]

Answer:

when you're going to need a designer a builder an electrical builder and a mechanic and you're going to need to be careful with what you use for all those things but the bike need to build you'll need a structure

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2 years ago
What is the steady-state value of the output of a system with transfer function G(s)= 6/(12s+3), subject to a unit-step input?
fenix001 [56]

Answer:

At steady state output will be 2

Explanation:

We have given transfer function G(S)=\frac{6}{12S+3}

Input is unit step so X(S)=\frac{1}{S}

We know that G(S)=\frac{Y(S)}{X(S)}, here Y(S), is output

So output Y(S)=G(S)\times X(S)

Y(S)=\frac{1}{S}\times \frac{6}{12S+3}

Taking 12 common from denominator

Y(S)=\frac{1}{2S(S+\frac{1}{4})}

Now using partial fraction

\frac{1}{2S(S+\frac{1}{4})}=\frac{A}{2S}+\frac{B}{(S+\frac{1}{4})}

\frac{1}{2S(S+\frac{1}{4})}=\frac{A(S+\frac{1}{4}+2BS)}{2S(S+\frac{1}{4})}

AS+\frac{A}{4}+2BS=1

On comparing coefficient A=4 and B = -2

Putting the values of A and B in Y(S)

Y(S)=\frac{4}{2S}-\frac{2}{S+\frac{1}{4}}

Now taking inverse la place

y(t)=2-2e^{\frac{-t}{4}}

Steady state means t tends to infinite

So output at steady state = y(t)=2-2e^{\frac{-\infty}{4}}

y(t)=2-0=2  

3 0
3 years ago
TOPO NÀO CÓ CẤU HÌNH ĐA ĐIỂM
bixtya [17]

Answer:

Tout à fait les gens sont nuls

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3 years ago
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You are hired as the investigators to identify the root cause and describe what should have occurred based on the following info
creativ13 [48]

Answer:

The mass of fuel added, which is 10,166.2 kg is less than 22,300 kg which is the mass of fuel required to travel from Toronto to Edmonton, the plane therefore crashed.

Explanation:

Since density ρ = m/v where m = mass of fuel and v = volume of fuel, we need to find the mass of each volume of fuel.

So, m = ρv now ρ = specific gravity × density of water = 0.803 × 1000 kg/m³ = 803 kg/m³.

To find the mass of the 7,682 L of fuel, its volume is 7,682 dm³ = 7,682 dm³ × 1 m³/1000 dm³ = 7.682 m³.

It's mass, m = 803 kg/m³ × 7.682 m³ = 6168.646 kg

To find the mass of the extra 4,916 L of fuel added, we have

m' = ρv' where v' = 4,916 L = 4,916 dm³ = 4916 dm³ × 1 m³/1000 dm³ = 4.916 m³

m' =  803 kg/m³ × 4.916 m³ = 3947.548 kg

So, the total mass of the fuel is m" = m + m' = 6168.646 kg + 3947.548 kg = 10116.194 kg ≅ 10,166.2 kg

<u>Since this mass of fuel added, which is 10,166.2 kg is less than 22,300 kg which is the mass of fuel required to travel from Toronto to Edmonton, the plane therefore crashed.</u>

4 0
3 years ago
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