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Tresset [83]
3 years ago
10

WILL GIVE BRAINLIEST

Chemistry
1 answer:
GarryVolchara [31]3 years ago
3 0
72 is the electron capacity for period 6
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What will the subscript for NH4 be?
alisha [4.7K]

Answer:

2

Explanation:

The subscript on Ammoniumwhich is (NH4) is 2.

Hope this helped!

4 0
3 years ago
How many carbon atoms are in the following molecule of isobutane? (ch3)3ch
wariber [46]
The subscript 3 outside of the parentheses means to multiply everything in the parentheses by 3, so it becomes a matter of addition:
3*(CH3) * (1 carbon atom)/(CH3) = 3 carbon atoms in (CH3)3
CH has one carbon atom and one hydrogen atom, so:
1 carbon atom in CH
Add both of them together, and you get 4 carbon atoms in isobutane
3 0
3 years ago
With proper illustration, show the bond<br>formation in CO2 and what type of bond is involved​
Ipatiy [6.2K]

Answer:

ㅍㅇㅎㅇㅎㅅㅇㅎ젖ㄴㄹ자

Explanation:

ㅔ볺ㄴㅍㅍ짜븐ㅍㄴㅎㄴ

4 0
4 years ago
Bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter
Alisiya [41]

Answer:Hence, the bond length in HCl is 125 pm.

Explanation:

Bond length : It is an average distance between the nuclei of two bonded atoms in a molecule.

Also given that bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter-nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Beyond this if atoms come closer to each other then their will be repulsion between them.

So, the bond length between the Hydrogen and Chlorine atom in HCl molecule is :

Bond length=radius _{hydrogen}+radius_{chlorine}=25pm+100pm=125pm

Hence, the bond length in HCl is 125 pm.

5 0
3 years ago
Read 2 more answers
A decorative "ice" sculpture is carved from dry ice (solid CO2) and held at its sublimation point of –78.5°C. Consider the proce
Leno4ka [110]

Answer:

The answers to the questions are;

a. The entropy of sublimation for carbon dioxide (the system) is  

134.07 J/Kmol.

b. The entropy of the universe for this reversible process is 376 J/K.

Explanation:

Entropy of sublimation is the entropy change experienced following the transformation of a mole of solid to vapor at  the temperature where the sublimation is taking place

a. We note that the mass of the solid CO₂ = 389 g

Molar mass of CO₂ = 44.01 g/mol

Number of moles of CO₂ in the sculpture = Mass/(Molar mass)

= (389 g)/(44.01 g/mol) = 8.84 Moles

Entropy of sublimation is given by

ΔS_{sublimation} = S_{vapor} - S_{solid} = \frac{\Delta H_{sublimation}}{T}

Where:

ΔH_{sublimation}  = 26.1 KJ/mol

T = Temperature = –78.5°C = ‪194.65‬ K

Therefore the amount of heat required to cause the 389 g of dry ice to sublime =    26.1 KJ/mol  × 8.84 Moles = 230.695 KJ

Therefore the entropy of sublimation = ΔS_{sublimation} = \frac{230.695 KJ}{194.65 K}

= 1.185 KJ/K

= 1185 J/K = 1185/8.84 J/Kmol = 134.07 J/Kmol

b. The entropy of the universe is given by;

ΔS_{universe} = \Delta S_{system} + ΔS_{surrounding}  

If the heat absorbed by the system is the same as the heat given off by the surrounding, then we have;

ΔS_{universe} = \frac{Q}{ T_{system}}  -\frac{Q}{T_{surrounding}}  

                =1.185 KJ/K - -\frac{230.695 KJ}{285.15K} = 1.185 KJ/K - 0.809 KJ/K = 0.376 KJ/K

= 376 J/K.

7 0
3 years ago
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