Answer:
Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
Explanation:
Let's apply the formula for freezing point depression:
ΔT = Kf . m
ΔT = 74.2°C - 73.4°C → 0.8°C
Difference between the freezing T° of pure solvent and freezing T° of solution
Kf = Cryoscopic constant → 5.5°C/m
So, if we replace in the formula
ΔT = Kf . m → ΔT / Kf = m
0.8°C / 5.5 m/°C = m → 0.0516 mol/kg
These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg
0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:
Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
The artificial fixation of nitrogen (N2) has enormous energy, environmental, and societal impact, the most important of which is the synthesis of ammonia (NH3) for fertilizers that help support nearly half of the world's population.
<h3>Artificial fixation of nitrogen</h3>
a) The equilibrium constant expression is Kp=PCH4 PH2 OP CO×PH 23.
(b) (i) As the pressure increases, the equilibrium will shift to the left so that less number of moles are produced.
(ii) For an exothermic reaction, with the increase in temperature, the equilibrium will shift in the backward direction.
(iii) When a catalyst is used, the equilibrium is not disturbed. The equilibrium is quickly attained
To learn more about equilibrium constant visit the link
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Answer:
The answer to your question is: Includes sulfur and gain two electrons
Explanation:
Includes Chlorine This option is wrong, Chlorine belongs to group VII.
Includes Sulfur This option is true, Group VI includes Oxygen, Sulfur, Selenium, Tellurium.
Gain 2 electrons
. This option is true, Elements in group VI have six valence electrons so they gain to electrons to become estable.
Tend to form +2 ions This option is wrong, this elements form -2 ions
Have 5 valence electrons This option is wrong, this elements have 6 valence electrons.
Answer:
The heat of the reaction is 105.308 kJ/mol.
Explanation:
Let the heat released during reaction be q.
Heat gained by water: Q
Mass of water ,m= 1kg = 1000 g
Heat capacity of water ,c= 4.184 J/g°C
Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C
Q=mcΔT
Heat gained by bomb calorimeter =Q'
Heat capacity of bomb calorimeter ,C= 4.643 J/g°C
Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C
Q'=CΔT'=CΔT
Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.
q= -(Q+Q')
q = -mcΔT - CΔT=-ΔT(mc+C)
Moles of propane =
0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.
The heat of the reaction will be:
<span>Answer:
Chemical equations are balanced in order to: 1) satisfy the Law of Conservation of Mass, and 2) establish the mole relationships needed for stoichiometric calculations. The Law of Conservation of Mass: The Law of Conservation of Mass states that mass cannot be created or destroyed.</span>
