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erik [133]
2 years ago
14

A 125-mL sample of an aqueous solution of the protein ovalbumin from chicken egg white contains 1.31 g of the dissolved protein

and has an osmotic pressure of 4.32 torr at 25°C. What is the molar mass of ovalbumin?
Chemistry
1 answer:
Stella [2.4K]2 years ago
7 0

The molar mass of the protein is 45095 g/mol.

The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound.

The expression of molar mass of protein is

M₂ = (W₂/P) (RT/V)

Given;

W₂ = 1.31g

P = 4.32 torr = 5.75 X 10⁻³ bar

R = 0.083 Lbar/mol/K

T = 25°C = 298.15 K

V = 125 ml = 0.125 L

Putting all the values in the above formula

M₂= (1.31 g/5.75 X 10⁻³ bar) X (0.083 Lbar/mol/K X 2)/0.125 L)

M₂ = 45095 g/mol

Thus, the molar mass of the protein is 45095 g/mol.

Learn more about the Molar mass with the help of the given link:

brainly.com/question/22997914

#SPJ4

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Consider a solution that contains both C6H5NH2 and C6H5NH3+. Calculate the ratio [C6H5NH2]/[C6H5NH3+] if the solution has the fo
Tcecarenko [31]

The question has incomplete information. The pH values are not discriminated. Let's do, as an example, to pH = 4.69.

Answer:

For pH = 4.69, [C₆H₅NH₂]/[C₆H₅NH₃⁺] = 0.708

Explanation:

C₆H₅NH₂ is a base, and, when in aqueous solution, forms a conjugate acid, which is C₆H₅NH₃⁺. The equilibrium between these two species makes a buffer, a solution that prevents the change in pH by the addition of base or acid.

The pH of a buffer can be calculated by the equation of Handerson-Halsebach:

pH = pKa + log[conjugate base]/[acid]

Where pKa = -logKa, and Ka is the equilibrium constant of the acid. For the base, the equilibrium constant, Kb, is equal to 7x10⁻¹⁰, and

Ka*Kb = Kw

Where Kw is the equilibrium constant for water 1.00x10⁻¹⁴, so Ka for the conjugate acid is:

Ka = 1.00x10⁻¹⁴/7.00x10⁻¹⁰

Ka = 1.43x10⁻⁵

pKa = 4.84

pH = 4.84 + log [C₆H₅NH₂]/[C₆H₅NH₃⁺] (By this step, the pH values given by the question must be substituted)

4.69 = 4.84 + log[C₆H₅NH₂]/[C₆H₅NH₃⁺]

log[C₆H₅NH₂]/[C₆H₅NH₃⁺] = - 0.15

[C₆H₅NH₂]/[C₆H₅NH₃⁺] = 10^{-0.15}

[C₆H₅NH₂]/[C₆H₅NH₃⁺] = 0.708

8 0
3 years ago
Why does acetic acid lose its buffering ability at very high pH values? Why does acetic acid lose its buffering ability at very
salantis [7]

Answer:

Because the optimal range of buffering for a formic acid potassium formate buffer is 2.74 ≤ pH ≤ 4.74.

Explanation:

Every buffer solution has an optimal effective range due to pH = pKa ± 1. Outside this range, there is not enough acid molecules or conjugate base molecules to sustain the pH without variation. There is a certain amount of both molecules that has to be in the solution to maintain a pH controlled.

Being for the formic acid the pKa 3.74, the optimal effective range is between 2.74 and 4.74.  Upper or lower these range a formic acid/potassium formate buffer does not work.

3 0
3 years ago
Specify the l and ml values for n = 4.
Bumek [7]

Answer : The specify the l and ml values for n = 4 are:

At l = 0,  m_l=0

At l = 1,  m_l=+1,0,-1

At l = 2,  m_l=+2,+1,0,-1,-2

At l = 3,  m_l=+3,+2,+1,0,-1,-2,-3

Explanation:

There are 4 quantum numbers :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of m_l will be -2, -1, 0, +1, +2.

Spin Quantum number : It describes the direction of electron spin. This is represented as m_sThe value of this is +\frac{1}{2} for upward spin and -\frac{1}{2} for downward spin.

As we are given, n = 4 then the value of l and ml are,

l = 0, 1, 2, 3

At l = 0,  m_l=0

At l = 1,  m_l=+1,0,-1

At l = 2,  m_l=+2,+1,0,-1,-2

At l = 3,  m_l=+3,+2,+1,0,-1,-2,-3

6 0
3 years ago
Balance the chemical equation. Based on the equation, how many grams of bromine are produced by the complete reaction of 11 gram
scoundrel [369]

Answer:

Explanation:

The balanced chemical equation is Cl2 + 2KBr → 2KCl + Br2. The amount of bromine is calculated as follows:

11.0 g KBr (1mol KBr/119.002g KBr * 1mol Br2/2mol KBr * 159.808g Br2/1mol Br2= 7.39 g Br2.)

5 0
3 years ago
A gas is contained in a horizontal cylinder with a moveable piston of cross-sectional area 0.33\text{ m}^20.33 m 2 . The region
-BARSIC- [3]

Answer:

0.02 m

Explanation:

∆U = q + w

w = ∆U - q = (1380 - 2040) J = -660 J

w = -p∆V = -pA∆h

∆h = -w/(pA)

p = 1 bar × (100000 Pa/1 bar) = 100000 Pa

∆h = -(-660 J)/(100000 Pa×0.33 m²) = 0.02 m

4 0
3 years ago
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