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Delicious77 [7]
2 years ago
8

What effect does pneumonia have on the diffusion of O2 and CO2 across the membranes in the lungs? a. slows diffusion b. complete

ly blocks diffusion c. accelerates diffusion d. has no effect e. reverses diffusion direction
Chemistry
1 answer:
GarryVolchara [31]2 years ago
5 0

Answer:

a. slows diffusion

Explanation:

Gas exchange on respiratory surfaces in the body (the lungs) occurs through a process known as diffusion. Blood which is low in oxygen and high in carbondioxide (carried from cells) goes through an exchange in the lung's alveoli (where oxygen concentration is high and carbondioxide is low). The oxygen in the alveoli diffuses into the blood, while the carbondioxide in the blood diffuses into the alveoli. This diffusion is possible because of the concentration gradient across the membranes.

Pneumonia is the inflammation of the lungs due to injury or infection. Liquid (pus) accumulates in the alveoli (a natural immune response to the infection or injury), a condition known as pulmonary edema which makes it harder for gases to be exchanged between the blood and the alveoli, thereby making breathing difficult. This slows down diffusion and if the condition is severe enough, can cause a respiratory failure where oxygen levels in the blood are critically low and carbondioxide levels are very high.

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What is the solubility of argon (in units of grams per liter) in water at 25 °C, when the Ar gas over the solution has a partial
beks73 [17]

Answer:

0.02405 g/L is the solubility of argon  in water at 25 °C.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{Ar}=K_H\times p_{gas}

where,

K_H = Henry's constant = 1.40\times 10^{-3}mol/L.atm

p_{Ar} = partial pressure of carbonated drink = 0.51atm

Putting values in above equation, we get:

C_{Ar}=1.40\times 10^{-3}mol/L.atm\times 0.430 atm\\\\C_{Ar}=6.02\times 10^{-4}mol/L

Molar mass of argon = 39.95 g/mol

Solubility of the argon gas :

6.02\times 10^{-4}mol/L\times 39.95 g/mol=0.02405 g/L

0.02405 g/L is the solubility of argon  in water at 25 °C.

5 0
3 years ago
For the decomposition of calcium carbonate, consider the following thermodynamic data (Due to variations in thermodynamic values
In-s [12.5K]

Answer : The temperature in kelvins is, T>1108.695K

Explanation : Given,

\Delta H = 178.5 KJ/mole = 178500 J/mole

\Delta S = 161.0 J/mole.K

Gibbs–Helmholtz equation is :

\Delta G=\Delta H-T\Delta S

As per question the reaction is spontaneous that means the value of \Delta G is negative or we can say that the value of \Delta G is less than zero.

\Delta

The above expression will be:

0>\Delta H-T\Delta S

T\Delta S>\Delta H

T>\frac{\Delta H}{\Delta S}

Now put all the given values in this expression, we get :

T>\frac{178500J/mole}{161.0J/mole.K}

T>1108.695K

Therefore, the temperature in kelvins is, T>1108.695K

7 0
3 years ago
Which type of acetylcholine receptor is present on postganglionic neurons
Sonja [21]

Answer:

Mescarinic and Nicotinic

Explanation:

Postganglionic fibers can be present in both sympathetic and parasympathetic divisions, their main difference resides in how in the sympathetic division the postganglionic fibers are adrenergic and use norepinephrine (noradrenalin) as a neurotransmitter, in the parasympathetic division, on the other hand, fibers are cholinergic and use acetylcholine as a neurotransmitter, the<em> postganglionic neurons of sweat glands release acetylcholine for the activation of muscarinic receptors, another kind of receptor for acetylcholine are nicotinic receptors </em>that act as transmembrane sodium/potassium channels, while muscarinic receptors need to act through intracellular proteins.

I hope you find this informatiou useful and interesting! Good luck!

4 0
3 years ago
Which of the following lists the correct symbol for the ion that tin forms when it loses 2 electrons, the correct classification
ser-zykov [4K]

Answer:

\huge\boxed{\sf Option \ A}

Explanation:

The symbol for TIN is Sn.

When Sn loses 2 electrons, it gets a double positive charge ( +2 ) and becomes \sf Sn ^{+2}.

It becomes a cation.

The name of Ion is Tin ( II ) Ion.

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
Read 2 more answers
Enter the balanced NET IONIC equation for the potentially unbalanced equation AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq).
Zigmanuir [339]

Answer:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Explanation:

Hello!

In this case, since the net ionic equations are ionic representations of the molecular equation in which the spectator ions (those at both reactants and products sides) are cancelled out, we first write the complete ionic equation for this reaction, considering that the solid silver chloride is not ionized due to its precipitation:

Ag^+(aq)+NO_3^-(aq)+Na^+(aq)+Cl^-(aq)\rightarrow AgCl(s)+Na^+(aq)+NO_3^-(aq)

Whereas the nitrate and sodium ions are cancelled out for the aforementioned reason as they are the spectator ions, to obtain:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Which is the required net ionic equation.

Best regards!

4 0
2 years ago
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