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taurus [48]
3 years ago
9

To balance a chemical equation, one: a. changes the subscripts of the formulas. b. changes the coefficients of the formulas. c.

eliminates some of the products or reactants. d. changes the chemical symbols of the elements.
Chemistry
1 answer:
AfilCa [17]3 years ago
4 0
<span>B. Changes the coefficients of the formulas.</span>
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The metal lithium has a diagonal relationship with the metal magnesium. true or false.
emmasim [6.3K]
False   .........................................                                                   
6 0
3 years ago
(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction
ale4655 [162]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2}   \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu}   \\\\m_{Cu}=0.380gCu

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3}   \\\\m_{AgNO_3}=2.03gAgNO_3

Best regards!

5 0
3 years ago
At a pressure of 19.95kPa, 35.8g of carbon dioxide at a temperature of 27.5C would result in what volume of gas?
adell [148]

Answer:

volume of gas=101.94L

Explanation:

Suppose given gas follows the ideality nature of gas

PV=nRT

n=35.8/44mol=0.814 mol

P=0.197atm

T=27.5C=300.5K

R=0.0821atm/mol/K

after putting all value we get,

V=101.94L

volume of gas=101.94L

3 0
2 years ago
The atomic number of fluorine is 9. How many electrons does an ion of fluorine have if it is represented by the symbol shown bel
Irina-Kira [14]
  • See charge on ion is -1 .

Hence it has taken 1 electron

Now first look at EC of Fluorine(F)

\\ \bull\sf\dashrightarrow 1s^22s^22p^5

  • Now one electron added .hence no of electrons is 10now

Look at the EC

\\ \bull\sf\dashrightarrow 1s^22s^22p^6

Or

\\ \bull\sf\dashrightarrow [He]

Option C is correct.

5 0
2 years ago
Read 2 more answers
What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?
tamaranim1 [39]
<h2>Answer:AlF_{3} </h2>

Explanation:

The chemical equation of the reaction that occurs when AlF_{3} reacts with O_{2} is

4AlF_{3}+3O_{2}→2Al_{2}O_{3}+6F_{2}

4 moles of AlF_{3} requires 3 moles of O_{2}.

1 mole of AlF_{3} requires \frac{3}{4} moles of O_{2}.

Given that we have 9 moles of AlF_{3}.

9 moles of AlF_{3} requires \frac{3}{4}\times 9=6.75 moles of O_{2}.

But we have 12 moles of O_{2}.

So,AlF_{3}  will be consumed first.

So,AlF_{3}  is the limiting reagent.

3 0
3 years ago
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