Binders ; fillers. They are inert substances to hold pill shape and preserve the medication, its ph / etc.
The empirical formula is = C2H4O2
Molecular formula=C2H4O2
<h3>Calculation of
Molecular formula and empirical formula:-</h3>
Vinegar has three elements:
oxygen = 53.29%,
hydrogen = 6.70%,
and carbon = 40.01%.
We can create an equation for the total mass of vinegar with 'a' carbon atom,' b' hydrogen atom, and 'c' oxygen atoms using the molar masses of C, H, and O.
12*a + 1*b + 16*c = 60
We also know that C makes up 24 g/mol, or 40.01 percent, of the overall mass of 60 g/mol.
The formula contains two C atoms because each C atom has a molecular mass of 12 g/mol. You may determine that the formula contains 4 H and 2 O atoms by using the same reasoning for H and O.
The empirical formula is = C2H4O2
Molecular formula= (C2H4O2)n
(4 x 12 + 1 x 4 + 16 x 2)n = 60
(84)n = 60
n=60/84
n=0.71=1
Molecular formula=C2H4O2
Learn more about Molecular and empirical formulas here:-
brainly.com/question/9207476
#SPJ4
Answer:
d = Hydrogen and oxygen are being formed.
Explanation:
When current is passed through the water electrolysis take place.
Water is splitted into hydrogen and oxygen gas. Because of this formation bubbles are formed.
At cathode:
2H₂O + 2e⁻ → H₂ + 2OH⁻
Cathode is negatively charged and reduction take place on it.
At anode:
4OH⁻ → O₂ + 2H₂O + 4e⁻
Anode is positively charged and oxidation take place on it.
The over all reaction can be written as:
Chemical equation:
2H₂O (electricity) → 2H₂ + O₂
The question is incomplete, here is the complete question:
A chemist adds 370.0 mL of a 2.25 M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist has added to the flask. Round your answer to 3 significant digits
<u>Answer:</u> The mass of iron (III) bromide is 246. grams
<u>Explanation:</u>
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

We are given:
Molarity of solution = 2.25 M
Molar mass of iron (III) bromide = 295.6 g/mol
Volume of solution = 370.0 mL
Putting values in above equation, we get:

Hence, the mass of iron (III) bromide is 246. grams