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qaws [65]
4 years ago
7

The temperature program for a separation starts at a temperature of 50 °C and ramps the temperature up to 270 °C at a rate of 10

°C/minute. Which statement is NOT true for this separation?
A) At 10 °C/minute, a total of 22 minutes is needed to reach 270 oC.
B) Strongly retained solutes will remain at the head of the column while the temperature is low.
C) Weakly retained solutes will separate and elute early in the separation.
D) The vapor pressure of strongly retained solutes will increase as temperature increases.
E) Strongly retained analytes will give broad peaks.
Chemistry
1 answer:
Troyanec [42]4 years ago
6 0

Answer:

The correct answer to the question is Option E (Strongly retained analytes will give broad peaks).

Explanation:

The other options are true because:

A. Initial temp = 50 °C

   Final temp =  270 °C

Differences in temp = 270 - 50 = 220°C

Rate =  10 °C/minute.

So, at 10 °C/minute,

total of 220°C /10 °C = number of minutes required to reach the final temp.

220/10 = 22 minutes

B. A column has a minimum and maximum use temperature. Solutes that are already retained would remain stationary while temperatures are low. This would only change if there is an increase in temperature. Heat transfers more energy to the liquid which would make the solute interact with the column phase.

C. Weakly retained solutes may contain larger molecules, will separate by absorbing into the solvent early in separation making the mobile phase separates out into its components on the stationary phase.

D. Retained solute's vapor pressure is higher at higher temperatures making it possible for particle to escape more from the solute when the temperature is high than when it is low.

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mafiozo [28]

Answer:

2.7 g/cm^3

Explanation:

D = m/V

D = 40.5 g / 15 cm^3

D =  2.7 g/cm^3

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How do you convert 134kj to Calories?
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3 years ago
Given a chemical equation, showing the dissociation of an acid in solution, be able to identify the "acid", the "base", the "con
Karo-lina-s [1.5K]

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory:

  • An acid is defined as a substance which looses donates protons and thus forming conjugate base
  • A base is defined as a substance which accepts protons and thus forming conjugate acid.

HA+H_2O\rightarrow A^-+H_3O^+

Suppose acid Ha is getting dissociated in its solution and after dissociation it donates its proton to water molecule and forms conjugate base. Where as water (acting as a base) accepts protons and forms conjugate acid.

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H_3O^+ = Conjugate acid

For example:

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Sulfuric acid dissociating in its solution to form conjugate base and conjugate acid.

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3 0
4 years ago
Question 14 of 25
belka [17]

double displacement

bcoz each of the reactants combines with other reactants to obtain the product

4 0
3 years ago
Which statements describes why ethyl methyl ether (b.p. 7.9°C) and 1-propanol (b.p. 97.2°C) have such different boiling points d
Lelu [443]

Answer:

B) 1-propanol has more hydrogen bonding than ethyl methyl ether.

Explanation:

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Ethyl methyl ether has both London dispersion forces and dipole-dipole interactions.

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1-propanol has more hydrogen bonding than ethyl methyl ether which explains why they both have different boiling points.

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3 years ago
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