Answer : Half life and radioactive decay are inversely proportional to each other.
Explanation :
The mathematic relationship between the half-life and radioactive decay :
................(1)
where,
N = number of radioactive atoms at time, t
= number of radioactive atoms at the beginning when time is zero
e = Euler's constant = 2.17828
t = time
= decay rate
when 
then the number of radioactive decay become half of the initial decay atom i.e 
.
Now substituting these conditions in above equation (1), we get
By rearranging the terms, we get
Now taking natural log on both side,
By rearranging the terms, we get
This is the relationship between the half-life and radioactive decay.
Hence, from this we conclude that the Half life and radioactive decay are inversely proportional to each other. That means faster the decay, shorter the half-life.
Answer:
Spreading out a wave over a larger area just causes the wave strength to weaken, but does not cause gaps to form. Therefore, if you look at photons as waves, spatial gaps never form in light as it travels through free space, no matter how dim it gets.Spreading out a wave over a larger area just causes the wave strength to weaken, but does not cause gaps to form. Therefore, if you look at photons as waves, spatial gaps never form in light as it travels through free space, no matter how dim it gets
Explanation:
Answer:
Furthermore, because hydrofluoric acid, HF, loses a proton, H+1, to generate its conjugate in the reaction that is shown above, this reactant can be classified as a Brønsted-Lowry acid, and, consequently, the fluoride ion, F–1, is the conjugate base of this acid.
Explanation:
hope this helps
Answer:
C₆H₁₂O₆ and O₂
Explanation:
To know which option is correct, it important that we know the concepts of chemical equation .
A chemical equation gives us an expression of a chemical reaction in terms of symbols and formula. There are two sides to every equation. The side bearing the reactant and the side bearing the product.
The reactant is located on the left side and the product is located on the right side.
Reactant —> Product
With the above information, let us answer the question given above.
6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂
The products are located on the right side of the equation.
Thus, the products of the reaction is C₆H₁₂O₆ and O₂
