The lewis dot structure rule states that
1 answer:
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The approximate molar mass of lauryl alcohol is 183 g/mol.
As per Raoult's law:
Tb = the freezing point of benzene (5.5oC), Ts = the freezing point of the solution, K = the cryoscopic constant (5.12 K*kg/mol for benzene), and Cm = the molality of the solution.
/M
=
where ml is the mass of lauryl alcohol and ms is the mass of the solvent.
=K
/M
Therefore, M==
=183 g/mol.
An organic substance called lauryl alcohol is created industrially from coconut or palm kernel oil. It is an alcoholic fat. The use of sodium lauryl sulfate and other sulfate esters of lauryl alcohol as surfactants is extremely common. In shampoos, sodium laureth sulfate, ammonium laureth sulfate, and sodium lauryl sulfate are all utilized. Lauryl alcohol has a floral scent and is flavorless and colorless. In addition to being a flavor-enhancing food additive, lauryl alcohol is also used to create medicines, lubricating lubricants, surfactants, and monolithic polymers. Lauryl alcohol is a kind of emollient used in cosmetics. Lauryl alcohol, a significant scent, and 1-bromododecane, an alkylating agent used to increase the lipophilicity of organic molecules, are both precursors to Lauryl alcohol.
A solution of 5. 00 g of lauryl alcohol in 0. 100 kg of benzene freezes at 4. 1°c. what is the approximate molar mass of lauryl alcohol?
Learn more about lauryl alcohol here:
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Answer:
See explanation below
Explanation:
First, we need to understand that the monochlorination of an alkane like this one, involves substitution of one of the atoms of hydrogen of the molecule for an atom of chlorine.
This reaction takes place when the alkane reacts with Cl₂ in presence of light or heat.
When this happens, the first step involves the breaking of the double bond of the chlorine to form the ion Cl⁻.
The next step involves the substraction of the hydrogen of the molecule by the Chlorine. This will leave the alkane with a lone pair available for reaction.
The third step, the alkane with the lone pair of electron substract a chlorine for the beggining and form the mono chlorinated product.
The final step involves forming the remaining products with the remaining reagents there.
In the picture attached you have the mechanism and product for this reaction:
