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Naya [18.7K]
4 years ago
12

1. A student gathered two boxes of the same size made of different materials: glass and clear plastic. She placed them on a wind

owsill in the sun for an hour and then measured the temperature of the air in each box. Which statement best describes the purpose of the experiment? to relate the type of box material to the temperature of the air within the box to relate the size of the box to the temperature of the air within the box to relate the type of box material to the mass of the box to relate the amount of time a box is exposed to sunlight to the temperature of the air within the box 2. What is the average time for the toy car to move 1.0 m on dirt? 20.2 s 24.4 s 28.1 s 60.7 s 3. A student collected data about the distance a ball falls over time. Which type of graph should he use to represent the data? circle graph scatterplot histogram bar graph
Physics
1 answer:
Kobotan [32]4 years ago
8 0

Answer:

1.  to relate the type of box material to the temperature of the air within the box

2. Question is incomplete

3. scatterplot

Explanation:

1. The only thing done differently in this experiment is the type of material used in making the boxes, hence the experiment must be about that. Before proceeding to answering this question, we must have this at the back of our minds.

We can gather from the experiment that the boxes are of the same size and were subjected to sunlight for an hour (the same time duration for both). Hence, the temperature of the air inside the box will only be affected by the type of material the box is made of since the boxes have the same size and were subjected to sunlight for the same duration.

From the options provided, the best description for this experiment is; to relate the type of box material to the temperature of the air within the box.

2. The question is incomplete. The value for speed/velocity needed to calculate the average time is missing.

However, the formula needed here is velocity = distance ÷ time

3. There are two variables in this experiment; distance and time

The type of graph that shows two variables on it (of the options provided) is the scatterplot.

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Answer:

because it can be hard

Explanation:

I said that because they be on bed rest

6 0
4 years ago
A small metal sphere has a mass of 0.19 gg and a charge of -23.0 nCnC. It is 10.0 cmcm directly above an identical sphere that h
RoseWind [281]

Answer:

  a = -7.29 m / s²

Explanation:

For this exercise we must use Newton's second law,

          F -W = m a

Force is electrical force

         F = k q₁ q₂ / r²

         k q₁ q₂ / r² -mg = m a

indicate that the charge of the two spheres is equal

         q₁ = q₂ = q

         a = (k q² / r² - m g) / m

         a = k q² / m r² - g

Let's reduce the magnitudes to the SI system

        m = 0.19 g (1kg / 1000 g) = 1.9 10⁻⁴ kg

        q1 = q2 = q = -23.0 nC (1C / 10⁹ nC) = -23.0 10⁻⁹ C

        r = 10.0 cm (1m / 100cm) = 0.1000 m

let's calculate

        a = 9 10⁹ (23.0 10⁻⁹)² / (0.1000² 1.9 10⁻⁴) - 9.8

        a = -7.29 m / s²

The negative sign indicates that the direction of this acceleration is downward

6 0
3 years ago
What is also known as watered carbons
faltersainse [42]
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5 0
3 years ago
Read 2 more answers
Two poles are connected by a wire that is also connected to the ground. The first pole is 20ft tall and the second pole is 10ft
Natasha2012 [34]

Answer: 31.6ft

Explanation:

Check the attachment for the diagram.

According to the right angle triangle AEC, we will use Pythagoras theorem to get |AC|. Note that |AE| = |AB| - |CD|

that is 20ft - 10ft = 10ft

According to the theorem, the square of the sum of the adjacent side and the opposite side is equal to the square of the hypotenuse.

|AE|^2 + |EC|^2 = |AC|^2

10^2 + 30^2 = |AC|^2

100 + 900 = |AC|^2

|AC| = √1000

|AC| = 31.6ft

Therefore, the wire should be anchored 31.6ft to the ground to minimize the amount of wire needed.

6 0
4 years ago
a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i
Katyanochek1 [597]
Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
             a = (Vf - Vi) / t
where a is acceleration,
Vf is final velocity,
Vi is initial velocity, and
t is time

Substituting,
            a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>

Part B: 
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
               F = m x a
where F is force,
m is mass, and 
a is acceleration

Substituting,
              F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

<em>ANSWER: 240 N </em>

Part C: 
The distance that the sprinter travel is calculated through the equation,
         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
             d = 13.5 m

<em>ANSWER: d = 13.5 m</em>

3 0
3 years ago
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