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2 years ago

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Of the following approximate conversions of celsius into fahrenheit, which is most accurate? a. 24°c almost-equals 75.9°f b. 2°c

almost-equals 35.8°f c. 34°c almost-equals 92.7°f d. 13°c almost-equals 55.0°f

1 answer:

Softa [21]2 years ago

4 0

The most accurate among the options is 13°c almost-equals 55.0°f, when you round down 55.4, you get 55.0

Hence, option D) is the most accurate.

<h3>What is Scale of Temperature?</h3>

Scale of temperature is simply a method used in calibrating the physical quantity of temperature in metrology.

Conversion of Celsius into Fahrenheit, Formula is expressed as;

Degree = (0 × 9/5) + 32 = Fahrenheit

First we check each option;

A) 24°c almost-equals 75.9°f

24°C = (24 × 9/5) + 32 = 75.2°F

B) 2°C almost-equals 35.8°f

2°C = (2 × 9/5) + 32 = 35.6°F

C) 34°C almost-equals 92.7°f

34°C = (34 × 9/5) + 32 = 93.2°F

D) 13°c almost-equals 55.0°f

13°C = (13 × 9/5) + 32 = 55.4°F

The most accurate among the options is 13°c almost-equals 55.0°f, when you round down 55.4, you get 55.0

Hence, option D) is the most accurate.

Learn more about temperature scales here: brainly.com/question/88395

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Un zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que el camino hay un inst

iren2701 [21]

Responder:

12374550,527 N / m²

Explicación:

Dado que:

Número de tacos = 10

Área de cada montante = 0.01 in²

Peso total de la persona = 180 libras

Usando la relación:

Presión = Fuerza / Área

La fuerza ejercida es el producto de la masa y la aceleración debido a la gravedad.

Masa = 180 libras = 81,47 kg

Aceleración por gravedad = 9,8 m / s²

Área total = (número de montantes * Área por montante) = (10 * 0.01) = 0.1 pulg²

Conversión a m²:

0,1 pulg² = 6,452 * 10 ^ -5 m²

Por lo tanto,

Presión = (81,47 * 9,8) / (6,452 * 10 ^ -5)

Presión = 798.406 / 0.00006452

Presión = 12374550.527 N / m²

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3 years ago

What is the frequency of an ocean wave that is traveling at a speed of 45 m/s if it has a wavelength of 3 meters.

V125BC [204]

Answer:

The frequency of an ocean wave is 15 Hz.

Explanation:

We are given with, the speed of an ocean wave is 45 m/s. Its wavelength is 3 m

It is required to find the frequency of an ocean wave.

The speed of a wave is given in terms of frequency and wavelength as :

$v=f\lambda$ ,

f = frequency of ocean wave

$f=\dfrac{v}{\lambda}\\\\f=\dfrac{45}{3}\\\\f=15\ Hz$

So, the frequency of an ocean wave is 15 Hz.

4 0

3 years ago

24 POINTS!!!!!!!!!!!!

Karo-lina-s [1.5K]

Answer: Option (c) is the correct answer.

Explanation:

When the child is tossed up into the air then she gains kinetic energy as the child has moved from its initial position.

It is given that mass is 20 kg, velocity is $5 m/s^{2}$ , and height is 2 m.

Calculate the kinetic energy of child as follows.

kinetic energy = $\frac{1}{2}mv^{2}$

= $\frac{1}{2}20 kg \times (5 m/s)^{2}$

= $10 kg \times 25 m^{2}/s^{2}$

= $250 kg m^{2}/s^{2}$

Also, when child falls off the ground then she will have gravitational potential energy.

Calculate gravitational potential energy of child as follows.

Potential energy = m × g × h

= $20 kg \times 9.8 m/s^{2} \times 2 m$

= $392 kg m^{2}/s^{2}$

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3 years ago

Read 2 more answers

Air is being pumped into a spherical balloon so that its volume increases at a rate of 150 cm3/s. How fast is the radius of the

Slav-nsk [51]

0.119cm/s is the radius of the balloon increasing when the diameter is 20 cm.

<h3>How big is a circle's radius?</h3>

The radius of a circle is the distance a circle's center from any point along its circumference. Usually, "R" or "r" is used to indicate it.

A circle's diameter cuts through the center and extends from edge to edge, in contrast to a circle's radius, which extends from center to edge. Essentially, a circle is divided in half by its diameter.

dv/dt = 150cm³/s

d = 2r = 20cm

r = 10cm

find dr/dt

Given that the volume of a sphere is calculated using

v = 4/3πr³

Consider both sides of a derivative

d/dt(v) = d/dt( 4/3πr³)

dv/dt = 4/3π(3r²)dr/dt = 4πr²dr/dt

Hence,

dr/dt = 1/4πr².dv/dt

dr/dt = 1/4π×(10)²×150

dr/dt = 1/4π×100×150

dr/dt = 0.119cm/s.

To know more about radius visit:

brainly.com/question/15053236

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3 0

1 year ago

If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and t

STatiana [176]

Answer:

The velocity is $4.6 m/s^2$

Explanation:

Given:

Force = 500N

Distance s= 0

To find :

Its velocity at s = 0.5 m

Solution:

$\sum F_{x}=m a$

$F\left(\frac{4}{5}\right)-F_{S}=13 a$

$500\left(\frac{4}{5}\right)-\left(k_{s}\right)=13 a$

$400-(500 s)=13 a$

$a = \frac{400 -(500s)}{13}$

$a = (30.77 -38.46s) m/s^2$

Using the relation,

$a=\frac{d v}{d t}=\frac{d v}{d s} \times \frac{d s}{d t}$

$a=v \frac{d v}{d s}$

$v d v=a d s$

Now integrating on both sides

$\int_{0}^{v} v d v=\int_{0}^{0.5} a d s$

$\int_{0}^{v} v d v=\int_{0}^{0.5}(30.77-38.46 s) d s$

$\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}$

$\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]$

$\left[\frac{v^{2}}{2}\right]=[15.385-4.807]$

$\left[\frac{v^{2}}{2}\right]=10.578$

$v^{2}=10.578 \times 2$

$v^{2}=21.15$

$v = \sqrt{21.15}$

$v = 4.6 m/s^2$

8 0

3 years ago