Answer: 10 cm3
Explanation:
Mass of sample of steel (m) = 80 grams
density of sample of steel (p) = 8 g/cm3 samples volume (v) = ?
Since density is obtained by dividing mass by volume, the density of the steel sample is expressed as:
density = mass / volume
p = m / v
make v the subject formula
v = m / p
v = 80 grams / 8 g/cm3
v = 10 cm3
Thus, the samples volume is 10 cm3
Answer:
density = 4.763pounds per liter
Explanation:
1g/cm³ = 2.205pounds per liter
2.16g/cm³ = (unknown)pounds per liter
(unknown)pounds per liter = 2.205 x 2.16 = 4.763
density = 4.763pounds per liter
Answer:
conductors
Explanation:
Because they consist of lattice of atoms with free electrons and these free electrons allows current to flow through.
Answer:
attractive force
Explanation:
hope this helps, pls mark brainliest :D
Answer: N = 2.78 × 10^23 atoms
There are N = 2.78 × 10^23 atoms in 70g of Au2cl6
Completed Question:
Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits
Explanation:
Given:
Molar mass of Au2cl6 = 303.33g/mol
Mass of Au2cl6 = 70g
Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol
According to the chemical formula of Au2cl6,
1 mole of Au2cl6 contains 2 moles of Au
Number of moles of Au = 2 × 0.231mol = 0.462mole
There are 6.022 × 10^23 atoms in 1 mole of an element.
Number of Atom of gold in 0.462 mole of gold is:
N = 0.462 mol × 6.022 × 10^23 atoms/mol
N = 2.78 × 10^23 atoms
