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mihalych1998 [28]
3 years ago
5

What is the scientific method?

Chemistry
1 answer:
OLEGan [10]3 years ago
6 0
D. A set of steps that help scientists gather knowledge
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Why are scientists worried that climate change will cause these toxic algae blooms to become more frequent?
ipn [44]

Answer: Eutrophication is the enhancement of the growth of algae in the water body.

Explanation:

The scientists are worried for the climate change as if the climate changed to prolonged rainy then the frequent raining can remove toxic chemicals from the agricultural sites, landfills, industries, and from other locations and deposit them to the water body (river, lakes, ponds, and others). The deposition of the salts of nitrogen, phosphorus, and sulfur promotes the growth of algae in the water body. This leads to reduction in the concentration of oxygen in the water body. This is called eutrophication. The lack of oxygen can lead to mortality of aquatic animals.

4 0
2 years ago
How is ozone produced?
zubka84 [21]
The answer is A. the solar ultraviolet ray breaks the molecule apart
3 0
3 years ago
Read 2 more answers
Why is Mm02 called manganese (IV) oxide?
Minchanka [31]

Answer:

MnO2 M n O 2 is an ionic substance without any oxo-anions, therefore its name has the -ide ending.

5 0
3 years ago
An alloy with an average grain diameter of 35 μm has a yield strength of 163 Mpa, and when it undergoes strain hardening, the gr
Lera25 [3.4K]

Answer:

\sigma_y\ =210.2\ MPa  

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

\sigma_y=\sigma_o+\dfrac{K}{\sqrt d}

\sigma_y\ =Yield\ strength

d = diameter

K =Constant

\sigma_o\ =material\ constant

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

163=\sigma_o+\dfrac{K}{\sqrt 35}      ------------1

d= 17 μm ,yield strength = 192 MPa

192=\sigma_o+\dfrac{K}{\sqrt 17}           ------------2

From equation 1 and 2

192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}

K=394.53

By putting the values of K in equation 1

163=\sigma_o+\dfrac{394.53}{\sqrt 35}

\sigma_o\ =96.31\ MPa

\sigma_y=96.31+\dfrac{394.53}{\sqrt d}

Now when d= 12 μm

\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}

\sigma_y\ =210.2\ MPa

4 0
3 years ago
Please help. thank youuuu
Dmitry [639]

Answer:

'See Explanation

Explanation:

Determine the [OH−] , pH, and pOH of a solution with a [H+] of 9.5×10−13 M at 25 °C.

Given [H⁺] = 9.5 x 10⁻¹³M => [H⁺][OH⁻] = 1.0 x 10⁻¹⁴ => [OH⁻] = 1.0 x 10⁻¹⁴/9.5 x 10⁻¹³ = 0.0105M

pH = -log[H⁺] = -log(9.5 x 10⁻¹³) = - (-1202) = 12.02.

pOH = -log[OH⁻] = -log(0.0105) = -(-1.98) = 1.98

Now you use the same sequence in the remaining problems.

6 0
3 years ago
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