The partial pressure of Hydrogen gas can directly be calculated
by simply taking the difference of the overall pressure and the vapour pressure
of water. That is:
P (H2 gas) = 759.2 torr – 23.8 torr
<span>P (H2 gas) = 735.4 torr</span>
Answer:
see explanation below
Explanation:
In this case, we have the following reaction:
Mg + 1/2O₂ -------> MgO
Now, according to this reaction we want to know the percent composition of MgO. The problem is not providing the mass of the initial reactants and the product, so we can use the atomic weights of the components, to do this
The molecular weight of Mg is 24.305 g/mol, and O is 15.999 g/mol, so, let's calculate the molar mass of MgO:
MM MgO = 24.305 + 15.999 = 40.304 g/mol
Now with this weight, let's see the percent composition of this compound:
%Mg = 24.305 / 40.304 * 100 = 60.304 %
%O = 15.999 / 40.304 * 100 = 39.696 %
And this would be the percent composition of MgO
Answer:
The correct option is: a. 0.12ml, p200
Explanation:
A pipette is a laboratory instrument, which is used to measure and transfer a particular volume of liquid. A pipette comes in various designs with differing levels of precision and accuracy.
An air displacement micropipette is an adjustable micropipette that can deliver about 0.1 µl to 1000 µl (1 ml) of liquid, depending upon the size.
A micropipette type P200 can deliver 20–200 µl liquid.
<u>Therefore, a P200 micropipette is used for measuring 0.12ml or 120µl liquid.</u>
Answer:
double replacement
Explanation: the two elements on each side switch
