The correct option is A) work.
Work is said to be done by a force when a force is exerted on an object and the the object on which the force is exerted moves in the direction of the force.
The amount of work done is given by the product of the force and the displacement made by the object.
Option (B) is incorrect, since Watt is the unit of power.
Option (C) is wrong, since joule is the unit of work or energy.
Option (D) is wrong, since power is the rate at which work is done.
To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as
The potential energy, 
The volume, 
The potential energy per unit volume is defined as the energy density.



The energy density related with electric field is given by

Here, the permitivity of the free space is

Therefore, rerranging to find the electric field strength we have,



Therefore the electric field is 2.21V/m
B Ik it all just know who they’ll you
the answer in my opinion would be A