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dalvyx [7]
3 years ago
6

Which image illustrates the interaction of a light wave with a mirror?

Physics
2 answers:
creativ13 [48]3 years ago
8 0

Answer:

I'm pretty sure its A

Explanation:

because its a reflection- Hope you get a good grade!

nadezda [96]3 years ago
3 0
100% it is A it has to be A
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___is when a force is exerted on an object and the object moves a distance in the direction of the force.
defon

The correct option is A) work.

Work is said to be done by a force when a force is exerted on an object and the the object on which the force is exerted moves in the direction of the force.

The amount of work done is given by the product of the force and the displacement made by the object.

Option (B) is incorrect, since Watt is the unit of power.

Option (C) is wrong, since joule is the unit of work or energy.

Option (D) is wrong, since power is the rate at which work is done.

5 0
3 years ago
Read 2 more answers
The lithosphere contains rocks, soils, and minerals.
sergij07 [2.7K]

Answer: TRUE

Explanation:

Hope this helped :))

4 0
2 years ago
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What electric field strength would store 12.5 JJ of energy in every 6.00 mm3mm3 of space?
Tcecarenko [31]

To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as

The potential energy,  U = 13.0 J

The volume,  V = 6.00 mm^3 = 6.00*10^{-9}m^3

The potential energy per unit volume is defined as the energy density.

u = \frac{U}{V}

u= \frac{(13.0 J)}{(6.00*10^{-9} m^3)}

u= 2.167109 J/m^3

The energy density related with electric field is given by

u = \frac{1}{2} \epsilon_0 E^2

Here, the permitivity of the free space is

\epsilon_0 = 8.85*10^-{12} C^2/N \cdot m^2

Therefore, rerranging to find the electric field strength we have,

E = \sqrt{\frac{2u}{\epsilon_0}}

E = \sqrt{\frac{2(2.167109)}{8.85*10^{-12}}}

E = 2.211010 V/m

Therefore the electric field is 2.21V/m

8 0
3 years ago
Question 2 10
ss7ja [257]
B Ik it all just know who they’ll you
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What unit is used to count atoms and molecules?
murzikaleks [220]

the answer in my opinion would be A

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