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3 years ago

The proportionality constant of the graph (y to x) is

Physics

1 answer:

ExtremeBDS [4]3 years ago

3 0

Answer:

y=kx was this helpful if I was give it the Brainiest

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How many calories are absorbed by a pot of water with a mass of 500g in order to raise the temperature from 20c to 30c?

LenaWriter [7]

Calories would denote the amount of heat.

Givens are:
Mass = 500 g
t0 = 20C
tf = 30C
C = 1 cal/gC

Formula:
Q=MCt

500g (1cal/gC) 10C= 5000 cal

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3 years ago

Distance and ___ are really the same quantity. A. length b. direction c. speed d. displacement

Oksi-84 [34.3K]

Answer:

distance and length are the same quantity

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3 years ago

Identify the normal force on the shopping cart after 75 newtons of groceries are added to the cart

Anna71 [15]

If the shopping cart is parallel to the ground, the weight is acting vertically downward, then force is equal to weight. The normal force will be acting perpendicular to the ground,and acting upward opposite of the weight.

3 0

3 years ago

Read 2 more answers

Consider a metal bar of initial length L and cross-sectional area A. The Young's modulus of the material of the bar is Y. Find t

RUDIKE [14]

Answer:

Spring constant = YA / L

Explanation:

Let F be the force being applied on cross sectional area A of metal bar due to which an extension of ΔL is obtained in the wire of length L then

stress = F / A

strain = ΔL /L

Young's modulus = ( F / A ) / (ΔL /L)

Y = ( F L / A ΔL )

( F / ΔL ) = ( YA / L )

Spring constant = ( F / ΔL )

Spring constant = YA / L

6 0

3 years ago

Two balls of equal mass collide and stick together as shown in the figure. The initial velocity of ball B is twice that of ball

Mice21 [21]

The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as

$\theta f = 26.3 \deg$
vf/vA= 0.94
2vf^2 / 5vA^2 = 0.35

<h3>What is Collison equilibrium?</h3>

According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.

Generally, the equation for Collison equilibrium is mathematically given as

For horizontal motion

mvAx+m2vAx = 2mvfx

For vertical motion

-mvAy+m2vAy = 2mvfy

vfy = 1/2 vAy

$\tan \theta f = vfy/vfx \\\\\tan \theta f = 1/3 vAy/vAx \\\\\tan \theta f = vAy/vAx \\\\\theta f = tan-1 ( 1/3 tan (56) )\\\\$

$\theta f = 26.3 \deg$

(b)

$v fy = vf sin \theta f\\\\vAy = vA sin theta i\\\\vf/vA = vfy/vAy sin( \theta i)/sin(\theta f)\\\\vf/vA = 1/2 sin(56)/sin(26.3) \\\\$

vf/vA= 0.94

(c)

$Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}$

2vf^2 / 5vA^2 = 0.35

In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others

$\theta f = 26.3 \deg$

vf/vA= 0.94

2vf^2 / 5vA^2 = 0.35