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2 years ago

Which type of radiation occur during nuclear processes? (Select all that apply)

Physics

1 answer:

Rainbow [258]2 years ago

7 0

Answer:

Particle radiation

Explanation:

nuclear process is in atom nucleas maybe emit the electron ,neutrino or anti-neutrino

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You’re still in a redecorating mood and want to move a 35kg bookcase to a different place in the living room. You exert 58 N on

CaHeK987 [17]

Answer: 0.16

Explanation:

Newton's second law states that the resultant of the forces exerted on the bookcase is equal to the product between the mass (m) and the acceleration (a):

$F-F_f = ma$

where

F = 58 N is the force applied

Ff is the frictional force

Substituting, we find the frictional force

$F_f = F-ma=58 N-(35 kg)(0.12 m/s^2)=53.8 N$

The frictional force has the form:

$F_f = \mu mg$

where $\mu$ is the coefficient of kinetic friction. Re-arranging the formula, we can find the coefficient:

$\mu=\frac{F_f}{mg}=\frac{53.8 N}{(35 kg)(9.8 m/s^2)}=0.16$

4 0

4 years ago

A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the

Maurinko [17]

Answer:

(a). The decay constant is $1.55\times10^{-5}\ s^{-1}$

The half life is 11.3 hr.

(b). The value of N₀ is $2.38\times10^{11}\ nuclei$

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity $R_{0}=10\ mCi$

Time $t_{1}=4\ hours$

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

$R=R_{0}e^{-\lambda t}$

$\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})$

Put the value into the formula

$\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})$

$\lambda=0.0000154\ s^{-1}$

$\lambda=1.55\times10^{-5}\ s^{-1}$

We need to calculate the half life

Using formula of half life

$T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}$

Put the value into the formula

$T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}$

$T_{\dfrac{1}{2}}=44.719\times10^{3}\ s$

$T_{\dfrac{1}{2}}=11.3\ hr$

(b). We need to calculate the value of N₀

Using formula of $N_{0}$

$N_{0}=\dfrac{3.70\times10^{6}}{\lambda}$

Put the value into the formula

$N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}$

$N_{0}=2.38\times10^{11}\ nuclei$

(c). We need to calculate the sample's activity

Using formula of activity

$R=R_{0}e^{-\lambda\times t}$

Put the value intyo the formula

$R=10e^{-(1.55\times10^{-5}\times30\times3600)}$

$R=1.87\ mCi$

Hence, (a). The decay constant is $1.55\times10^{-5}\ s^{-1}$

The half life is 11.3 hr.

(b). The value of N₀ is $2.38\times10^{11}\ nuclei$

(c). The sample's activity is 1.87 mCi.

4 0

4 years ago

Which waves move perpendicular to their energy?

Step2247 [10]

Transverse waves move perpendicular to their energy

3 0

3 years ago

Ephemeral streams ________.

nikdorinn [45]

Answer: B. have flowing water either episodically or during only a portion of the year

Explanation:

Ephemeral stream is a type of temporary stream that flows after rainfall or precipitation. Such streams are seasonal streams and are common in extremely dry or arid regions. This type of stream is not connected to any other water source either ground water or surface water except from rainfall, such streams ceases to flow after the raining season and dry off.

6 0

3 years ago

Ethan pushes a wooden box across a carpeted floor. Then he pushes the same box across a smooth marble floor. Why does Ethan find

Ksju [112]

Answer:

B.The box experiences less friction on the marble floor

Explanation:

8 0

3 years ago

Read 2 more answers