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3 years ago

12

Kenya has a pile of salt on the counter. She uses a pinch of it for a meal. Which of the following physical properties of the sa

lt change?
A. Density
B. Shape
C. Solubility
D. Thermal conductivity

2 answers:

JulsSmile [24]3 years ago

5 0

The answer is C. I just did this test and got a 100

SashulF [63]3 years ago

4 0

C. I learned about this last year

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Which use of a simple machine changes the direction of a force? A. using a ramp to load boxes onto a truck B. using an axe to sp

kiruha [24]

A. <span> using a ramp to load boxes onto a truck </span>

8 0

2 years ago

1. A jogger jogs 25 m East, stops to rest, then continues for 10 more meters

Komok [63]

Answer:

35m

Explanation:

25m + 10m = 35m east.

*(adding since it's in the same direction)

8 0

2 years ago

A thin copper rod 1.0 m long has a mass of 0.050 kg and is in a magnetic field of 0.10 t. What minimum current in the rod is nee

slamgirl [31]

Answer:

$i = 4.9 A$

Explanation:

Force on a current carrying rod due to magnetic field is given as

$F = iLB$

here we know that

$i =$ current in the rod

$B = 0.10 T$

$L = 1.0 m$

now magnetic force is balanced by the weight of the rod

so we will have

$iLB = mg$

$i(1.0)(0.10) = 0.05 \times 9.8$

$i = 4.9 A$

8 0

2 years ago

a student lift a 25kg mass at vertical distance of 1.6m in a time of 2.0 seconds. a. Find the force needed to lift the mass (in

zhannawk [14.2K]

Answer:

a. F = 245 Newton.

b. Workdone = 392 Joules.

c. Power = 196 Watts

Explanation:

Given the following data;

Mass = 25kg

Distance = 1.6m

Time = 2secs

a. To find the force needed to lift the mass (in N );

Force = mass * acceleration

We know that acceleration due to gravity is equal to 9.8

F = 25*9.8

F = 245N

b. To find the work done by the student (in J);

Workdone = force * distance

Workdone = 245 * 1.6

Workdone = 392 Joules.

c. To find the power exerted by the student (in W);

Power = workdone/time

Power = 392/2

Power = 196 Watts.

5 0

2 years ago

You use a pulley system to lift a car engine. You apply a force of 120n and the pulley pulls on the engine with a force of 1050n

Savatey [412]

Given,

Effort force = 120 N

Load force= 1050 N

Mechanical advantage of a pulley is given by the ratio of load force to the effort force.

$M.A=\frac{Load force}{Effort force}$

$=\frac{1050}{120}$

$=8.75$

Therefore, the mechanical advantage of the given pulley is 8.75.

5 0

2 years ago

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