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3 years ago

What rule does static electricity follow

Physics

1 answer:

arsen [322]3 years ago

7 0

Static electricity works when there is an imbalance of positive and negative charges, and thus causes a little spark.

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y en el número racional (Q) se puede escribir como conciente de dos números enteros (z)o como un desimal periódico.Espresa el 1/

umka21 [38]

Answer:

Sorry I don't understand this language I'm sorry

6 0

3 years ago

a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car m

padilas [110]

Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N

Explanation:

Acceleration is the rate of change of velocity.
It is given by the equation, a = change in velocity/time

Here, velocity changes from 0 to 27 m/s and time = 8

⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²

Force is calculated by the equation, F = Mass × Acceleration
This is based on Newton's second law of motion.

Here, mass of the car = 1500 kg and a = 3.375 m/s²

⇒ Force = 1500 × 3.375 = 5062.5 N

4 0

3 years ago

If two waves are out of phrase with each other and are moving through the same medium what will they undergo

zvonat [6]

some form of destructive interference. if phase is 180 degrees out, destructive = darkfringe or quiet in sound

4 0

3 years ago

(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32º ramp at a speed

stiks02 [169]

a) 7 buses

b) 6.8 m

Explanation:

The motion of the motorcycle is a projectile motion, so it consists of 2 independent motions:

- A uniform motion along the horizontal direction

- A uniformly accelerated motion along the vertical direction

The initial components of the velocity of the motorcycle are:

$v_x = u cos(32^{\circ})=(40.0)(cos 32^{\circ})=33.9 m/s\\v_y = u sin(32^{\circ})=(40.0)(sin 32^{\circ})=21.2 m/s$

The equation for the vertical motion of the motorcycle is

$y=h+u_y t - \frac{1}{2}gt^2$

where

y is the altitude at time t

h is the initial height

$g=9.8 m/s^2$ is the acceleration due to gravity

The bus top is at the same height of the initial ramp, so we have

$y=h$

And therefore, we can solve the equation for t, to find the time of flight:

$0=u_y t - \frac{1}{2}gt^2\\t(u_y-\frac{1}{2}gt)=0\\t=\frac{2u_y}{g}=\frac{2(21.2)}{9.8}=4.33 s$

Now we find what is the horizontal distance covered by the motorcycle in its jump, which is given by:

$d=v_x t = (33.9)(4.33)=146.8 m$

And since each bus has a length of L = 20.0 m, the number of buses that the motorcycle can clear with its jump is:

$n=\frac{d}{L}=\frac{146.8}{20}=7.34$

So, 7 buses.

In the previous problem, we saw that the total range of the motion of the motorcycle is

$d=146.8 m$

And we said that this corresponds to 7 buses.

Each bus has a length of

L = 20 m

So, the total length of 7 buses is

$L' = 7L=7(20)=140 m$

Therefore, the range of the motorcycle is greater than the length of the buses by:

$\Delta x = d-L'=146.8-140 = 6.8 m$

which means he will miss the last bus by 6.8 meters.

6 0

3 years ago

A student practicing for a track meet ran 250 m in 30 seconds. What was her average speed?

artcher [175]

8.33 meters/sec. time = 30 sec. 30 sec. = 8.33 meters/sec.

5 0

3 years ago

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