Answer:
2 Atm; 2.016 g
Explanation:
Changing the volume without changing the temperature or mass only changes the pressure. Volume and pressure are inversely proportional so halving the volume will double the pressure.
P = 1 Atm, T = 0 °C are "standard" temperature and pressure (STP). The volume of 1 mole of gas is 22.4 L under these conditions. That means the amount of hydrogen gas in the cylinder is 1 mole, so has a mass of 2.016 g.
After the volume reduction, the pressure is 2 Atm, and the mass remains 2.016 g.
Answer:
A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.
Explanation:
Answer: 0.55L
Explanation:
Given that,
Original volume of balloon (V1) = 0.3L
Original temperature of balloon (T1) = 25.0°C
[Convert 25.0°C to Kelvin by adding 273
25.0°C + 273 = 298K]
New volume of balloon (V2) = ?
New temperature of balloon (T2# = 275.0°C
[Convert 25.0°C to Kelvin by adding 273
275.0°C + 273 = 548K]
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
0.3L/298K = V2/548K
To get the value of V2, cross multiply
0.3L x 548K = 298K x V2
164.4L•K = 298K•V2
Divide both sides by 298K
164.4L•K /298K = 298K•V2/298K
0.55L = V2
Thus, the new volume of the balloon would be 0.55 litres
Answer:
This is a precipitation reaction in which Ni(OH)₂ precipitates.
8.68%
Explanation:
Let's consider the following reaction.
Ni²⁺(aq) + 2 NaOH(aq) ⇄ Ni(OH)₂(s) + 2 Na⁺(aq)
This is a precipitation reaction in which Ni(OH)₂ precipitates.
We can establish the following relations:
- The molar mass of Ni(OH)₂ is 92.71 g/mol.
- 1 mole of Ni(OH)₂ is produced per 1 mole of Ni²⁺.
- The molar mass of Ni²⁺ is 58.69 g/mol.
When 343 mg (0.343 g) of Ni(OH)₂ are collected, the mass of Ni²⁺ that reacted is:
The mass percent of nickel in the 25.0g-sample is: