<u>Given:</u>
Concentration of Ba(OH)2 = 0.348 M
<u>To determine:</u>
pOH of the above solution
<u>Explanation:</u>
Based on the stoichiometry-
1 mole of Ba(OH)2 is composed of 1 mole of Ba2+ ion and 2 moles of OH- ion
Therefore, concentration of OH- ion = 2*0.348 = 0.696 M
pOH = -log[OH-] = - log[0.696] = 0.157
Ans: pOH of 0.348M Ba(OH)2 is 0.157
Answer: False
Explanation: adding heat to matter results in thermal energy.
Los hongos si son bacterias
Answer:
Explanation:
the molar mass for Na2CO3 is 2*23+12+3*16=106 g/mole
106*0.251=26.606 grames
The answer
the general for of the equation of reaction is
N2 + 3 H2 ------------ 2NH3
1mol 3mole 2 mole
nH2 nNH3
(nX means number of mole of X)
according to the law of proportion
3 / nH2 = 2 / nNH3 (E)
nNH3 = m NH3 / 17.03 , and m NH3 = <span>0.575 g
consequently </span>nNH3 = 0.575 g / 17.03 = 0.03 mol
by considering (E) 3 / nH2 = 2 / 0.03 = 66.66, and nH2 = 3 / 66.66 =0.045
finally we can write
mH2 = nH2 x 2.0158 =0.045 x 2.0158 = 0.09 g