Answer:
202 L
Explanation:
Step 1: Write the balanced equation
C₆H₁₂O₆ + 6 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(l)
Step 2: Calculate the moles corresponding to 270 g of C₆H₁₂O₆
The molar mass of C₆H₁₂O₆ is 180.16 g/mol.
270 g × 1 mol/180.16 g = 1.50 mol
Step 3: Calculate the moles of CO₂ generated from 1.50 moles of glucose
The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of CO₂ formed are 6/1 × 1.50 mol = 9.00 mol
Step 4: Calculate the volume of 9.00 moles of CO₂ at STP
The volume of 1 mole of an ideal gas at STP is 22.4 L.
9.00 mol × 22.4 L/mol = 202 L
The average speed is 160 meters a minute.
Answer:
The answer to your question is letter D. 2.02 g
Explanation:
Data
moles of Ne = 0.100
atomic mass of Neon = 20.18 g
Process
1.- Use proportions to find the answer
20.18 g of Ne ------------------ 1 mol of Ne
x ------------------ 0.1 moles
x = (0.1 x 20.18)/1
x = 2.018
2.- Consider the significant figures
0.100 has three significant figures so the answer must be 2.02 g
The fraction of the original amount remaining is closest to 1/128
<h3>Determination of the number of half-lives</h3>
- Half-life (t½) = 4 days
- Time (t) = 4 weeks = 4 × 7 = 28 days
- Number of half-lives (n) =?
n = t / t½
n = 28 / 4
n = 7
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 100 g
- Number of half-lives (n) = 7
- Amount remaining (N)=?
N = N₀ / 2ⁿ
N = 100 / 2⁷
N = 0.78125 g
<h3>How to determine the fraction remaining </h3>
- Original amount (N₀) = 100 g
- Amount remaining (N)= 0.78125 g
Fraction remaining = N / N₀
Fraction remaining = 0.78125 / 100
Fraction remaining = 1/128
Learn more about half life:
brainly.com/question/26374513
Answer:
option C = Reactant: 4NH₃ + 6NO → product: 5N₂ + 6H₂O
Explanation:
Chemical equation:
NH₃ + NO → N₂ + H₂O
Balanced chemical equation:
4NH₃ + 6NO → 5N₂ + 6H₂O
Ammonia is react with nitrogen mono oxide and produced nitrogen and water.
Ammonia and nitrogen monoxide are reactants while water and nitrogen are product.
Four number of moles of ammonia react with six nitrogen monoxide and produced five mole of nitrogen and six mole of water.
