Ask question

Ask question

All categories

3 years ago

5

Express 410,000 in scientific notation

1 answer:

suter [353]3 years ago

6 0

Answer:

4.1 * 10^5

Explanation:

410,000

As we can see, there are 4 zero and 1 number 1 after the first number so the number when written in scientific notation would be:

4.1 * 10^5

Hope this can help you :3

You might be interested in

Which element is used to reduce metal oxides and make pure metals?

Setler [38]

Can vary. Carbon is used quite commonly, and extracts metal oxides, works with zinc, iron, tin, lead and copper.

5 0

3 years ago

If an atom has a mass number of 23, which of the following is always true?

lesantik [10]

Atomic number is less than 11

8 0

3 years ago

In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?

dedylja [7]

<u>Answer:</u> The correct answer is $2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)$

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

<u>Reaction 1:</u> $2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

<u>Reaction 2:</u> $CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

<u>Reaction 3:</u> $HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

<u>Reaction 4:</u> $2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

<u>Reaction 5:</u> $SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)$

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is $2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)$

6 0

3 years ago

The molecular weight of an organic compound was determined by measuring the freezing point depression of a benzene solution. A 0

Rudiy27

<u>Answer:</u> The molar mass of the sample is 120.6 g/mol

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$\Delta T_f$ = depression in freezing point = 0.42°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point elevation constant = 5.065°C/m

$m_{solute}$ = Given mass of solute (sample) = 0.500 g

$M_{solute}$ = Molar mass of solute (sample) = ? g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 50.0 g

Putting values in above equation, we get:

$0.42^oC=1\times 5.065^oC/m\times \frac{0.500\times 1000}{M_{solute}\times 50.0}\\\\M_{solute}=\frac{1\times 5.065\times 0.500\times 1000}{50.0\times 0.42}=120.6g/mol$

Hence, the molar mass of the sample is 120.6 g/mol

5 0

4 years ago

Which subatomic particle has negligible mass and travels around outside the nucleus?

nikdorinn [45]

Electrons travel around the nucleus

6 0

4 years ago