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3 years ago

I need help with this please and an explanation so i can understand ASAP!!!!

Mathematics

1 answer:

faltersainse [42]3 years ago

5 0

Answer:

17 feet

Step-by-step explanation:

8 squared is 64

15 squared is 225

225 + 64 = 289

289 square root is 17

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Find the value of the variables

Ierofanga [76]

Answer:

Your answer is.....

x= 10.58

y= 21.66

Mark it as brainlist answer . follow me for more answer.

Step-by-step explanation:

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3 years ago

Trapezoid W′X′Y′Z′ is the image of trapezoid WXYZ under a dilation through point C.

IRINA_888 [86]

Formula for scale factor
=image devide object
the answer is c

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3 years ago

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Which values of a, b, and c represent the answer in simplest form?<br><br> 7/9 * 4/9 = a b/c

myrzilka [38]

Answer:

Option 2: A=1, B=3, C=4

Step-by-step explanation:

7/9÷4/9 = 7/9*9/4
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4 0

2 years ago

Can someone help me with my math please?

LUCKY_DIMON [66]

Answer:

okkkkkkkkkkkk

Step-by-step explanation:

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8 0

2 years ago

Read 2 more answers

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago