Answer:
the volume occupied by 3.0 g of the gas is 16.8 L.
Explanation:
Given;
initial reacting mass of the helium gas, m₁ = 4.0 g
volume occupied by the helium gas, V = 22.4 L
pressure of the gas, P = 1 .0 atm
temperature of the gas, T = 0⁰C = 273 K
atomic mass of helium gas, M = 4.0 g/mol
initial number of moles of the gas is calculated as follows;

The number of moles of the gas when the reacting mass is 3.0 g;
m₂ = 3.0 g

The volume of the gas at 0.75 mol is determined using ideal gas law;
PV = nRT

Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.
1 mol of any particles = 6.02*10²³ particles
56 mol*6.02*10²³ molecules of water/1 mol =3.37*10²⁵
Answer:
I would say that a sauce is a mixture, only because everything that makes up a sauce is all mixed together and turned into one thing, it isn't all separate.
Answer:
2Al+3CuCl2=>3Cu + 2AlCl3
NH4Cl catalyses the oxidation of Cu
1 is correct, i’m not sure if that’s the answer your looking for because of the wording, but if it’s a multiple choice answer then that’s it