Sample cost = $15.796
<h3>Further explanation</h3>
Given
Mass = 2 g
Density = 0.718 g/ml
Cost = $5.67 per mL
Required
Cost
Solution
The density : the ratio of mass and volume
Can be formulated :
Density (ρ) = m : V
The volume of the liquid :
V = m : ρ
V = 2 g : 0.718 g/ml
V = 2.786 ml
Sample cost :
= 2.786 ml x $5.67/ml
= $15.796
5.76 g of are consumed when is burned to yield 5.3 grams of .
<h3>
What is a mole?</h3>
A mole is defined as 6.02214076 × of some chemical unit, be it atoms, molecules, ions, or others.
Calculating moles of
Number of mole of =
= = 0.12 mol
As is clear from the reaction stoichiometry, 9 moles of are consumed to yield 6 moles of .
Calculating the number of moles of
= 0.18 mol
Mass of consumed is = 0.18 X 32.0 =2.7 g =5.76 g
Hence, 5.76 g of are consumed when is burned to yield 5.3 grams of .
Learn more about mole here:
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Answer:
Oxidation
Explanation:
Mg loses 2e- for it to gain it's stability hence the reaction above is oxidation
note: Oxidation is the loss of electrons while reduction is the gain of electrons
Answer:
15.63.
Explanation:
So, from the question, we are given the following parameters or data or information for solving this particular Question and they are;
(1). "semi-permeable membrane from the extracellular space ([galactose] = 2 mM) to the cytosol ([galactose] = 10 mM) under biochemically standard conditions. (R = 0.08206 L atm/mol K = 8.314 J/mol K) (15 pts.) "
(2). "If ATP hydrolysis liberates 30.5 kJ/mol at standard conditions".
(3). " (507.2 g/mol) would be required to transport 260 g of galactose from the extracellular space to the cytosol"
Step one: determine the difference to transport of galactose from extracellular space to cytosol.
This can be done by using the formula below:
Ratio = intracellular/ extracellular.
=> 10/2 = 5 mM.
Step two: so, from statement (2) and (3), the if 507.2 g/mol ATP = 30.5 kJ/mol, then 260 g/mol = ???
Therefore, 260 × 30.5 / 507.2 = 15.63 is the energy required.