All categories

2 years ago

If you put 1000 J of heat energy into a bar of titanium and the bar's temperature rose

Chemistry

1 answer:

melisa1 [442]2 years ago

3 0

Answer:

The mass of the bar is approximately 0.33 g.

Explanation:

q (heat in joules) = 1000 J

c (specific heat capacity) = 52 J/g°C

ΔT (change in temperature) = 80 - 22 = 58°C.

m (mass in grams) = ?

m = q / cΔT

m = 1000 J / (52 J/g°C) (58°C)

m = 0.33 g

hope this helps and is right!! p.s. i really need brainliest :)

You might be interested in

Which element family is all 2-

Zielflug [23.3K]

Answer:

Alkaline Earth Metals

Explanation:

4 0

4 years ago

For many purposes we can treat methane as an ideal gas at temperatures above its boiling point of . Suppose the temperature of a

Elza [17]

Answer:

The volume decreases 5.5%

Explanation:

First, the question is incomplete, you are not giving the values of the temperatures and the pressure. However, I managed to find one similar question, and the given data is the temperature is lowered from 21 °C to -8°C, and the pressure decreased by 5%. If your data is different, you should only replace your data in the procedure, and you'll get an accurate result.

Now, with this data, let's see what we can do.

If this is an ideal gas, the equation to use is:

PV = nRT

Now, we know that this gas is suffering a decrease in temperature and pressure, but the moles stay the same so:

n₁ = n₂ = n

The constant R, is the same for both conditions. The only thing that differs here is the volume, temperature, and pressure. Therefore:

P₁V₁ = nRT₁ -----> n = P₁V₁ / RT₁

Doing the same with the pressure and volume 2 we have:

n = P₂V₂ / RT₂

Equalling both expressions and solving for V₂:

P₁V₁ / RT₁ = P₂V₂ / RT₂

V₂ = P₁T₂V₁ / P₂T₁

Now, as we know that P2 is 5% decreased from P1, so P2 = 0.95P1:

V₂ = P₁T₂V₁ / 0.95P₁T₁

The values of temperature in K:

T1 = 21+273 = 294 K

T2 = -8 + 273 = 265 K

Finally, let's calculate the volume:

V₂ = 264*P₁*V₁ / 294*0.95*P₁ ----> P cancels out

V₂ = 264V₁ / 294*0.95

V₁ = 0.945V₂

With this, we can day that Volume 2 decreases.

Now the percentage change would be using the following expression:

%V = (V₁ - V₂ / V₁) * 100

Replacing the data we have:

%V = V1 - 0.945V₁ / V₁

%V = 0.055V₁ / V₁ * 100

%V = 5.5%

7 0

3 years ago

The process in which rock fragments freeze to the bottom of a glacier and then are carried away when the glacier moves is called

guapka [62]

Im pretty sure its called plucking

3 0

3 years ago

Read 2 more answers

How many grams of NaCl are required to make 150.0 mL of a 5.000 m solution

Oksi-84 [34.3K]

The grams of NaCl that are required to make 150.0 ml of a 5.000 M solution is 43.875 g

calculation

Step 1:calculate the number of moles

moles = molarity x volume in L

volume = 150 ml / 1000 = 0.15 L

= 0.15 L x 5.000 M = 0.75 moles

Step 2: calculate mass

mass = moles x molar mass

molar mass of NaCl = 23 + 35.5 = 58.5 mol /L

mass is therefore =0.75 moles x 58.5 mol /l =43.875 g

4 0

3 years ago

Read 2 more answers

Cytochromes are critical participants in the electron transport chains used in photosynthesis and cellular respiration. How do c

goblinko [34]

Answer:

4) Each cytochrome has an iron‑containing heme group that accepts electrons and then donates the electrons to a more electronegative substance.

Explanation:

The cytochromes are proteins that contain heme prosthetic groups. Cytochromes undergo oxidation and reduction through loss or gain of a single electron by the iron atom in the heme of the cytochrome:

$Cytochrome-Fe²⁺ ⇄ cytochrome-Fe³⁺-e⁻$

The reduced form of ubiquinone (QH₂), an extraordinarily mobile transporter, transfers electrons to cytochrome reductase, a complex that contains cytochromes b and c₁, and a Fe-S center. This second complex reduces cytochrome c, a water-soluble membrane peripheral protein. Cytochrome c, like ubiquinone (Q), is a mobile electron transporter, which is transferred to cytochrome oxidase. This third complex contains the cytochromes a, a₃ and two copper ions. Heme iron and a copper ion of this oxidase transfer electrons to O₂, as the last acceptor, to form water.

Each transporter "downstream" is more electronegative than its neighbor "upstream"; oxygen is located in the inferior part of the chain. Thus, the electrons fall in an energetic gradient in the electron chain transport to a more stable localization in the electronegative oxygen atom.

7 0

3 years ago