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IRINA_888 [86]
3 years ago
9

Acid formulas can be distinguished from base formulas because acid formulas usually and base formulas .

Chemistry
1 answer:
sineoko [7]3 years ago
3 0

Answer:

A.  begin with hydrogen; pair a metal with a hydroxide ion

Explanation:

Acid can be distinguished from base on the basis of formulas in such a way that acid formula start with hydrogen.

For example:

Hydrochloric acid is strong acid. Its formula is HCl.

It start with hydrogen

Sulfuric acid is acid. Its formula is H₂SO₄

it is also start with hydrogen.

Base:

Base is distinguish from acid in such a way that in base formula metal is pair with hydroxide ion.

For example:

Sodium hydroxide is base. Its formula is NaOH.

sodium is metal while OH is hydroxide ion.

Potassium hydroxide is base. its formula is KOH.

potassium is metal and OH is hydroxide ion.

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you are heating a solution and recording its temperature every 2 min during an experiment. which is your independent variable an
Zepler [3.9K]
An independent variable is the variable you are changing in order to measure the dependent variable, which is what you are measuring.

In this example, the

independent variable: chemicals in solution
dependent variable: temperature of solution
7 0
3 years ago
if i add water to 100 mL of a 0.75 M NaOH solution un til the final volume is 165mL what will the molarity of the diluted soluti
ehidna [41]
Answer is: <span>the molarity of the diluted solution 0,454 M.
</span>V₁(NaOH) = 100 mL ÷ 1000 mL/L = 0,1 L.
c₁(NaOH) = 0,75 M = 0,75 mol/L.
n₁(NaOH) = c₁(NaOH) · V₁(NaOH).
n₁(NaOH) = 0,75 mol/L · 0,1 L.
n₁(NaOH) = 0,075 mol
n₂(NaOH) = n₁(NaOH) = 0,075 mol.
V₂(NaOH) = 165 mL ÷ 1000 mL/L = 0,165 L.
c₂(NaOH) = n₂(NaOH) ÷ V₂(NaOH).
c₂(NaOH) = 0,075 mol ÷ 0,165 L.
c₂(NaOH) = 0,454 mol/L.
7 0
3 years ago
6. El oxígeno gaseoso se calienta a presión constate de 50 °C a 300 K. Se conoce que inicialmente el volumen del sistema era de
frez [133]

Answer:

El volumen final del sistema es 1.2L

Explanation:

La ley de Charles establece que el incremento de la temperatura de un gas produce un incremento en el volumen directamente proporcional cuando la presión permanece constante. La ecuación es:

V₁/T₁ = V₂/T₂

<em>Donde V es volumen y T temperatura absoluta de un gas en 1, el estado inicial y 2, su estado final.</em>

<em />

Reemplazando:

V₁ = 1.3L

T₁ = 50°C + 273.15K = 323.15K

V₂ = Incógnita

T₂ = 300K

1.3L/323.15K = V₂/300K

1.2L = V₂

<h3>El volumen final del sistema es 1.2L</h3>
3 0
3 years ago
When 2.16g of H2 reacts with excess O2 by the following equation, 258 kJ of heat are released. What is the change of enthalpy as
alekssr [168]

Answer:

-241 kJ/mol

Explanation:

Let's consider the reaction of hydrogen with excess oxygen to form water.

2 H₂ + O₂ ⟶ 2 H₂O

When 2.16g of hydrogen reacts with excess oxygen, 258 kJ of heat are released, that is, Q = -258 kJ. Considering that the molar mass of hydrogen is 2.02 g/mol, the change of enthalpy associated with the reaction of 1.00 mol of hydrogen gas is:

ΔH° = -258 kJ/2.16 g × (2.02 g/1.00 mol) = -241 kJ/mol

8 0
3 years ago
What are the Products in this Chemical Reaction? PLEASE ANSWER ASAP!!
Nookie1986 [14]

Answer:

ZnCl2 + H2

Explanation:

4 0
3 years ago
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