Answer:
The correct answer is A Energy leaves the iron bar and enters the wood until the temperature are equal.
Explanation:
According to the law of conservation of energy or the first law thermodynamics energy neither be created nor destroyed, energy is transferred from one form to another form.
Here iron bar is placed in wood block energy is transferred from iron bar to wood until the temperatures are equal.
3. they make up larger compounds like fats and amino acids, would be the correct answer.
Answer:
HClO (l) → H⁺ (aq) + ClO⁻ (aq)
proton and hypochlorite.
Explanation:
HClO (Hypochlorous acid)
This is a weak acid that can be dissociated as this:
HClO (l) → H⁺ (aq) + ClO⁻ (aq)
proton and hypochlorite.
It is a weak acid, so it can adopt a Ka for its equilibrium
HClO + H₂O ⇄ H₃O⁺ + ClO⁻ Ka
Molar mass = 52.46 g/m
Assuming that the solution is simply an aqueous solution
so that it is purely made of NaClO4 (the solute) and water (the solvent), then
I believe the dissolved species would only be the ions of NaClO4, these are:
Na+
ClO4 -
Refer to the diagram shown below.
The piston supports the same load W at both temperatures.
The ideal gas law is

where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant
State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter
State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter
Because V, n, and R remain the same between the two temperatures, therefore

If the supported load is W kg, then

Similarly,


Because p₁/p₂ = T₁/T₂, therefore

The minimum piston diameter at 150 C is 20.8 cm.
Answer: 20.8 cm diameter